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3 years ago

An atom with 7 protons, 6 neutrons, and 7 electrons has an atomic mass of _____ amu. (Enter a whole number.)

Chemistry

2 answers:

umka2103 [35]3 years ago

6 0

It has a mass of 13 amu.
Hope this helps!

Damm [24]3 years ago

3 0

Answer : An atom with 7 protons, 6 neutrons, and 7 electrons has an atomic mass of 13 amu.

Explanation :

As we are give that,

Number of protons = 7

Number of electrons = 7

Number of neutrons = 6

As we know that,

Atomic number =Number of protons = Number of electrons = 7

Atomic mass = Number of neutrons + Atomic number

Atomic mass = 6 + 7 = 13 amu

Therefore, the atomic mass is, 13 amu

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Chlorine has two isotopes. The isotope with a mass of 34.969 amu has a relative abundance of 75.77%. The isotope with a mass of

Mars2501 [29]

34.969*.7577+36.966*.2433=35.489

5 0

2 years ago

Read 2 more answers

Rank the following particles, from largest to smallest in mass: alpha particle, beta particle, proton.

Len [333]

The best and most correct answer among the choices provided by your question is the fourth choice.

The correct arrangement of these particles from largest to smallest mass is: proton, alpha particle, beta particle.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

8 0

3 years ago

Read 2 more answers

2.Which of the alcohols listed below would you expect to react most rapidly with PBr3?A)CH3CH2CH2CH2CH2CH2OHB)(CH3CH2)2CH(OH)CH2

Gnoma [55]

Answer:

A) CH3CH2CH2CH2CH2CH2OH

Explanation:

For this question, we have the following answer options:

A) CH3CH2CH2CH2CH2CH2OH

B) (CH3CH2)2CH(OH)CH2CH3

C) (CH3CH2)2CHOHCH3

D) (CH3CH2)3COH

E) (CH3CH2)2C(CH3)OH

We have to remember the reaction mechanism of the substitution reaction with $PBr_3$ . The idea is to generate a better leaving group in order to add a "Br" atom.

The $PBr_3$ attacks the "OH" generation new a bond to P (O-P bonds are very strong), due to this new bond we will have a better leaving group that can remove the oxygen an allow the attack of the Br atom to generating a new C-Br bond. This is made by an Sn2 reaction. Therefore we will have a faster reaction with primary substrates. In this case, the only primary substrate is molecule A. So, "CH3CH2CH2CH2CH2CH2OH" will react faster.

See figure 1

I hope it helps!

7 0

3 years ago

0.68 moles of calcium to calcium atoms

Oksanka [162]

$0.68 \: moles \: calcium \times \frac{6.02 \times {10}^{23} \: calcium \: atoms }{1 \: mole \: calcium} \\$

The (( mole calcium ))s are simplified so the answer is based on the number of calcium atoms.

$0.68 \times 6.02 \times {10}^{23} = 68 \times {10}^{ - 2} \times 602 \times {10}^{ - 2} \times {10}^{23} \\$

$= 68 \times 602 \times {10}^{ - 4} \times {10}^{23} = 40936 \times {10}^{19} \\$

$calcium \: atoms = 40936 \times {10}^{19} \\$

_________________________________

And we're done.

Thanks for watching buddy good luck.

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3 0

3 years ago

Aluminum nitrate reacts with sodium hydroxide to form a precipitate of aluminum hydroxide. What mass of aluminum hydroxide will

lora16 [44]

Answer:

The mass of aluminum hydroxide that will precipitate when 35.5 mL of 0.145 mol/L aqueous aluminum nitrate is mixed with 44.2 mL of 0.215 mol/L aqueous sodium hydroxide is approximately 0.247 grams

Explanation:

The given parameters are;

The volume of 0.145 mol/L aqueous aluminum nitrate in the reaction = 35.5 mL

The volume of 0.215 mol/L aqueous sodium hydroxide in the reaction = 44.2 mL

The balanced chemical equation for the reaction is given as follows;

Al(NO₃)₃ (aq) + 3NaOH (aq) → Al(OH)₃ (s) + 3NaNO₃ (aq)

Therefore;

1 mole of Al(NO₃)₃, reacts with 3 moles of NaOH to form 1 mole Al(OH)₃, and 3 moles of NaNO₃

The number of moles of aqueous aluminum nitrate in the reaction = 35.5/1000 L × 0.145 mol/L = 0.0051475 moles

The number of moles of aqueous sodium hydroxide in the reaction = 44.2/1000 L × 0.215 mol/L = 0.009503 moles

Therefore, 0.009503 moles NaOH will react with 0.009503/3 moles Al(NO₃)₃ to form 0.009503/3 moles of aluminum hydroxide precipitate

The molar mass of aluminum hydroxide = 78 g/mol

Therefore, 0.009503/3 moles of aluminum hydroxide weighs 78 × 0.009503/3 = 0.247078 grams

The mass of aluminum hydroxide that will precipitate out ≈ 0.247 grams.

7 0

2 years ago