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Mashutka [201]
3 years ago
12

Determine the mass in grams of 3.57 mol al

Chemistry
1 answer:
Lynna [10]3 years ago
5 0
Determining the mass of a compound or any substance from its number of moles, you would need data on its molar mass since it allows the conversion from moles to grams and grams to moles. For aluminum, it has an atomic mass of 26.98 g/mol.

3.57 mol Al ( 26.98 g / mol ) = 96.32 g Al
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What happens to population growth in a logistic growth pattern as it reaches carrying capacity?
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37.9 grams of an unknown substance undergoes a temperature increase of
jenyasd209 [6]

Answer:

1.023 J / g °C

Explanation:

m = 37.9 grams

ΔT = 25.0*C

H = 969 J

c = ?

The equation relating these equation is;

H = mcΔT

making c subject of formulae;

c = H / mΔT

c = 969 J / (37.9 g * 25.0*C)

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4 0
3 years ago
What temperature would 3.54 moles of xenon gas need to reach to exert a pressure of 1.57 atm at a volume of 34.6 l
ira [324]

Answer:

186.9Kelvin

Explanation:

The ideal gas law equation is PV = n R T

where

P   is the pressure of the gas

V   is the volume it occupies

n  is the number of moles of gas present in the sample

R  is the universal gas constant, equal to  0.0821 atm L /mol K

T  is the absolute temperature of the gas

Ensure units of the volume, pressure, and temperature of the gas correspond to R ( the universal gas constant, equal to  0.0821 atm L /mol K )

n = 3.54moles

P= 1.57

V= 34.6

T=?

PV = n R T

PV/nR = T

1.57 x 34.6/3.54 x 0.0821

54.322/0.290634= 186.908620464= T

186.9Kelvin ( approximately to 1 decimal place)

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3 years ago
What is the precipitation reaction of sodium nitrate and lead (II)?
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The precipitation reaction of sodium nitrate and lead (II) chloride would not happen. No reaction will happen between these substances. Hope this answers the question. Have a nice day.
8 0
3 years ago
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