The taste and odors in fruit are often the result of:

Chemistry

2 answers:

Tasya [4]3 years ago

7 0

Answer:

Esters present in them.

Explanation:

Esters are organic compounds which are considered to be derivative of carboxylic acids. They are formed from reaction of carboxylic acid with a corresponding alcohol.

The general formula of an ester is RCOOR'.

The fruits generally get their odors and taste due to present of these natural esters.

For example: An ester called Ethyl-2-methyl butyrate is a responsible for taste and odor of fruits like apple, orange, strawberry, etc.

Tom [10]3 years ago

3 0

The taste and odors in fruits are often the result of the ester components of the fruits. Esters are organic compounds produced from the reaction of alcohol and carboxylic acid. For example, bananas have esters called isomyl acetate, citrus fruits have octyl acetates familiar in oranges, lemon, tangerine, grapefruits, etc., and many others.

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It is 762 miles from here to Chicago. An obese physics teacher jogs at a rate of 5.0 miles every 20.0 minutes. How long would it

Lina20 [59]

Answer:

3,048 minutes

Explanation:

762 divided by 5

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2 years ago

a faucet is leaking water at a speed of 5 drops per minute. If 1 ml is equivalent to 10 drops, how many liters of water will be

nikdorinn [45]

Answer: 0.72 litres of water is wasted in one day.

Explanation:

First you need to find out how many minutes are in a day. Do this by multiplying the number of minutes in an hour (60) by the number of hours in a day (24). 24 x 60 = 1440. If the faucet is dripping at 5 drops per minute, then multiply 5 by the number of minutes in a day (1440) to see how many drops drip in one day. 5 x 1440 = 7200. Now we need to figure out how many mL fo water that is. if 10 drops is 1 mL, then we need to divide the total number of drops (7200) by 10. 7200 divided by 10 is 720. That means 720 mL of water is dripping per day. Finally, we must convert mL to litres. There are 1000 mL in one litre, so divide 720 by 1000. The final answer is 0.72

6 0

2 years ago

What is the pH of a mixture of 0.042 M NaH2PO4 and 0.058 M Na2HPO4? Hint: The pKa of phosphate is 6.86.

AlekseyPX

Answer:

The pH value of the mixture will be 7.00

Explanation:

Mono and disodium hydrogen phosphate mixture act as a buffer to maintain pH value around 7. Henderson–Hasselbalch equation is used to determine the pH value of a buffer mixture, which is mathematically expressed as,

$pH=pK_{a} + log(\frac{[Base]}{[Acid]})$

According to the given conditions, the equation will become as follow

$pH=pK_{a} + log(\frac{[Na_{2}HPO_{4} ]}{[NaH_{2}PO_{4}]})$

The base and acid are assigned by observing the pKa values of both the compounds; smaller value means more acidic. NaH₂PO₄ has a pKa value of 6.86, while Na₂HPO₄ has a pKa value of 12.32 (not given, but it's a constant). Another more easy way is to the count the acidic hydrogen in the molecular formula; the compound with more acidic hydrogens will be assigned acidic and vice versa.

Placing all the given data we obtain,

$pH=6.86 + log(\frac{0.058}{0.042})$