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Evgen [1.6K]
3 years ago
12

A sample of water and alcohol are mixed. What method should be used to separate them? -Screening -Filtering -Fractional distilla

tion -density
Chemistry
2 answers:
Vlad [161]3 years ago
7 0

Answer;

Fractional distillation

Explanation;

-Fractional distillation is one of the method that is used to separate mixtures. It is used for the separation of miscible liquids, for example water and alcohol.

-Fractional distillation is a distillation method that is used to separate  liquids that dissolve in each other. It involves separating the components of a mixture by repeated distillations and condensations.

-The components in the mixture being separated by this method normally have different but close boiling points. For example a mixture of alcohol and water, they have different but close boiling points, thus during distillation alcohol condenses out as the first fraction followed by water.

PilotLPTM [1.2K]3 years ago
7 0
Fractional Distillation
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Under standard-state conditions, which of the following species is the best reducing agent? a. Ag+ b. Pb c. H2 d. Ag e. Mg2+
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<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

Reducing agents are defined as the agents which help the other substance to get reduced and itself gets oxidized. They undergo oxidation reaction.

X\rightarrow X^{n+}+ne^-

For determination of reducing agents, we will look at the oxidation potentials of the substance. Oxidation potentials can be determined by reversing the standard reduction potentials.

For the given options:

  • <u>Option a:</u>  Ag^+

This ion cannot be further oxidized because +1 is the most stable oxidation state of silver.

  • <u>Option b:</u>  Pb

This metal can easily get oxidized to Pb^{2+} ion and the standard oxidation potential for this is 0.13 V

Pb\rightarrow Pb^{2+}+2e^-;E^o_{(Pb/Pb^{2+})}=+0.13V

  • <u>Option c:</u>  H_2

This metal can easily get oxidized to H^{+} ion and the standard oxidation potential for this is 0.0 V

H_2\rightarrow 2H^++2e^-;E^o_{(H_2/H^{+})}=0.0V

  • <u>Option d:</u>  Ag

This metal can easily get oxidized to Ag^{+} ion and the standard oxidation potential for this is -0.80 V

Ag\rightarrow Ag^{+}+e^-;E^o_{(Ag/Ag^{+})}=-0.80V

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This ion cannot be further oxidized because +2 is the most stable oxidation state of magnesium.

By looking at the standard oxidation potential of the substances, the substance having highest positive E^o potential will always get oxidized and will undergo oxidation reaction. Thus, considered as strong reducing agent.

From the above values, the correct answer is Option b.

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