The balanced reaction is
3Na3PO4 + 2CuSO4 ------> 3Na2SO4 + Cu3(PO4)2
To balance this reaction of double displacement, we see first that this reaction maintain the valence numbers of every atom.
Then, to have the same value of Na in the two sides of the reaction we multiply for the number of the other side. So,
(Na3PO4)x 2
(Na2SO4)x3
As we can see either, we need to balance PO4 cause there are two molecules of this in the reactant side, so we have two molecules of PO4 in the product either.
Then we get
3Na3PO4 + 2CuSO4 ------> 3Na2SO4 + Cu3(PO4)2
To probe that balance was correct, you can verify that the charges are exactly the opposite.
Answer:

Explanation:
1. Calculate the mass of each element

2. Calculate the moles of each element

3. Calculate the molar ratios
Divide all moles by the smallest number of moles.

4. Round the ratios to the nearest integer
C:H = 1:2
5. Write the empirical formula
The empirical formula is 
Answer:- The volume of copper is 280 mL.
Solution:- Density and mass of copper metal are given and it asks to calculate the volume of it.
Density is directly proportional to mass and inversely proportional to the volume. The density formula is:

where D stands for density, M stands for mass and V stands for volume.
Since, the problem asks to calculate the volume, let's rearrange the formula for volume.

The given density is 8.9 grams per mL and the mass is 2.5 kg. We need to convert the mass unit from kg to g so that the g unit could be canceled while calculating volume.
The conversion factor is, 1kg = 1000g

= 2500g
Let's plug in the values in the density formula to calculate the volume.

= 280.89 mL
If the sig figs are considered then the answer needs to be round to two sig figs and hence the volume becomes 280 mL.
According to Le Chatelier's principle, adding additional reactant to a system will shift the equilibrium to the right, towards the side of the products. ... By Le Chatelier's principle, we can predict that the amount of methanol will increase, thereby decreasing the total change in CO.