All categories

3 years ago

I NEED HELP PLEASE, THANKS! :)

Chemistry

1 answer:

vaieri [72.5K]3 years ago

8 0

Answer:

This process is known as doping. It can be done by adding either of two types of impurity to the crystal.

(A) By adding electron rich impurities i.e., group 15 elements to the silicon and germanium of group 14 elements.

hope it's helpful

You might be interested in

Equation of ethane to ethanoic acid

VMariaS [17]

Feb 16, 2012 ... How do you convert ethane to ethanoic acid? (with equation please). First you chlorinate it in presence of light. C2H6 + Cl2 ---hv -> C2H5Cl + ...

Preparation of ethanoic acid from ethane This free online course covers the preparation of ethanoic acid from ethane. The Contents tab displays all the lessons ...

he formation of the aldehyde is shown by the simplified equation: ... Note: The equation for the conversion of ethanol to ethanoic acid is worked out in detail ... Starting from ethanenitrile, you would therefore get a solution containing ethanoate ... Mar 3, 2012 ... As well as using a normal type of molecular formula to describe an organic .... In ethane the carbon atoms have the maximum number of hydrogen atoms bonded .... e.g. ethanoic acid and ethanol will produce ethyl ethanoate,.

8 0

3 years ago

During a chemical reaction, two hydrogen atoms combine with two oxygen atoms. How many hydrogen and oxygen atoms will be present

Reil [10]

Answer:

2 hydrogen and 1 oxygen atoms

Explanation:

3 0

2 years ago

When 231. mg of a certain molecular compound X are dissolved in 65. g of benzene (CH), the freezing point of the solution is mea

Elan Coil [88]

Answer:

Molar mass X = 18.2 g/mol

Explanation:

Step 1: Data given

Mass of compound X = 231 mg = 0.231 grams

Mass of benzene = 65.0 grams

The freezing point of the solution is measured to be 4.5 °C.

Freezing point of pure benzene = 5.5 °C

The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

ΔT = i*Kf*m

⇒ΔT = the freezing point depression = 5.5 °C - 4.5 °C = 1.0 °C

⇒i = the Van't hoff factor = 1

⇒Kf = the freezing point depression constant for benzene = 5.12 °C/m

⇒m = the molality = moles X / mass benzene

m = 1.0 / 5.12 °C/m

m = 0.1953 molal

Step 3: Calculate moles X

Moles X = molality * mass benzene

Moles X = 0.1953 molal * 0.065 kg

Moles X = 0.0127 moles

Step 4: Calculate molar mass X

Molar mass X = mass / moles

Molar mass X = 0.231 grams / 0.0127 moles

Molar mass X = 18.2 g/mol

5 0

3 years ago

WILL GIVE BRAINLIEST!! Determine the volume of a container that holds 2.4 mol of gas at STP.

kykrilka [37]

Answer:

2.4 mol x 22.4 liter = 53.76 liters

1 mole

Explanation:

5 0

3 years ago

A large piece of jewelry has a mass of 132.6 g. a graduated cylinder initially contains 48.6 ml water. when the jewelry is subme

Simora [160]

Answer:- Density is 10.5 grams per mL and the substance is Silver(Ag).

Solution:- Mass of jewelry is given as 132.6 g. Initial volume of water in the graduated cylinder is 48.6 mL and the volume becomes 61.2 mL when this jewelry is submerged in the cylinder.

So, the volume of the jewelry = 61.2 mL - 48.6mL = 12.6 mL

We know that, $density=\frac{mass}{volume}$

Let's plug in the values in the above formula to calculate the density:

$density=\frac{132.6g}{12.6mL}$

$density=10.5\frac{g}{mL}$

So, the density of the jewelry is $10.5\frac{g}{mL}$ .

The substance from which the jewelry is made could easily be identified by comparing the calculated density with the density values given for different substances in the density table.

Looking at the density table, 10.5 grams per mL is the density for silver. So, the jewelry is made up from Silver.

4 0

3 years ago