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zzz [600]
3 years ago
8

PLEASE HELP 5 MIN LEFT

Chemistry
1 answer:
wlad13 [49]3 years ago
6 0

Answer:

there go my email

Explanation:

How are proteins built using the information provided by a molecule of RNA? ... RNA determines the sequence of amino acids in proteins and polypeptides by a two-step process: transcription of DNA produces mRNA in the nucleus, then translation of the mRNA to tRNA takes place in the ribosome in the cytoplasm.

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No caso da pessoa ser um atleta profissional,essa demanda de energia pode subir até 5400Kcal. Transforme essa medida de energia
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Answer:

If you speak Any English i Think I will be able to help you Los Amigo

Explanation:

6 0
3 years ago
What general trend applies to solubility?
Marysya12 [62]

Answer:

Basically, solubility increases with temperature. It is the case for most of the solvents. The situation is though different for gases. With increase of the temperature they became less soluble in each other and in water, but more soluble in organic solvents.

5 0
2 years ago
Get me the answers please
shutvik [7]

Answer:

a is a opinon answer

Explanation:

3 0
2 years ago
Read 2 more answers
If irons temperature goes from 50c to 75c in a 20g sample, how many joules of heat were used?
Marina CMI [18]

Answer:

Option D. 230 J

Explanation:

We'll begin by calculating the temperature change of the iron. This can be obtained as follow:

Initial temperature (T₁) = 50 °C

Final temperature (T₂) = 75 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 75 – 50

ΔT = 25 °C

Thus, the temperature change of the iron is 25 °C.

Finally, we shall determine the amount of heat energy used. This can be obtained as follow:

Mass (M) = 20 g

Change in temperature (ΔT) = 25 °C

Specific heat capacity (C) = 0.46 J/gºC

Heat (Q) =?

Q = MCΔT

Q = 20 × 0.46 × 25

Q = 230 J

Thus, the amount of heat used was 230 J

3 0
3 years ago
Using Equation (10), calculate [Ag+] in the cell, where it is in equilibrium with 1 M Cl- ion. (Ecell in Equation (10) is the ne
mixer [17]

Answer:

7.16x10⁻⁸M = [Ag+]

Explanation:

Using the equation:

E(Cell) =E⁰ - 0.0592/2 • log ([Cu2+]/[Ag+]²)

<em>Where E</em>⁰<em>= 0.4249V</em>

<em>E(Cell) = -(-0.0019V) -Measured value-</em>

<em>[Cu2+] = 1M</em>

<em />

Replacing:

0.0019V = 0.4249V - 0.0592/2 • log (1M/[Ag+]²)

-0.423V = - 0.0296 • log (1M/[Ag+]²)

14.29 = log (1M/[Ag+]²)

1.95x10¹⁴ = 1M / [Ag+]²

[Ag+]² = 5.12x10⁻¹⁵M

7.16x10⁻⁸M = [Ag+]

5 0
2 years ago
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