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never [62]
3 years ago
13

How many chloride ions are in 1.5 moles of aluminum chloride?

Chemistry
1 answer:
schepotkina [342]3 years ago
7 0

AlCl3 = Al3+ + 3Cl- = 4 ions

1 mol AlCl3 = Al3+ + 3Cl- = 4 x 6.023 x 10^23 ions

Hence, 1.5 moles of Aluminum Chloride, AlCl3 = 1.5 x 4 x 6.023 x 10^23 ​ions = 36.14 x 1023 ​ions

Therefore, 36.14 x 10^23 ​ions are there in 1.5 moles of Aluminum Chloride, AlCl3

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You need to do something like that your self so sorry can help.

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If the concentrated form of blood expander is 9.0 mol/L and one of your companions, a nurse, tells you that you need to have a f
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Answer:

0.032 L or 32 mL

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3 years ago
Write the lewis structure for mgi2. draw the lewis dot structure for mgi2. include all lone pairs of electrons.
viktelen [127]
Lewis Structure is drawn in following steps,

1) Calculate Number of Valence Electrons:
    
# of Valence electrons in Mg  =  2
# of Valence electrons in I      =  7
# of Valence electrons in I      =  7
                                               ---------
Total Valence electrons          =  16

2) Draw Mg as a central atom surround it by two atoms of Iodine.

3) Connect each Iodine atom to Mg, and subtract two electrons per bond. In this case we will subtract 4 electrons from total valence electrons. i.e.

Total Valence electrons           16
- Four electrons                    -   4
                                              ----------
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4) Now start adding the remaining 12 electrons on more electronegative atoms i.e. Iodine.

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3 years ago
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Answer:

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Answer:

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