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2 years ago

Explain what the star looks like to Jane

2 answers:

7 0

The star looks like a desirable hunk of masculinity to Jane. But to John, the star looks like a wimpy momma's boy who might compete with him for Jane's attention. Jane and John have different impressions of the star because of their gender-specific instincts that have evolved during thousands of millenia of human evolution.

zimovet [89]2 years ago

6 0

This is what I wrote for my project on this exact question! Hope this helps!

Now, Jane and John are in a different situation, observing stars through a telescope. The Doppler effect is also true for light emitted by stars, but instead of hearing the difference, you see the difference in their color. You know if a star is coming or going from the color it emits. Based on how close and in what direction the star is moving, the star can look very different. One person could be looking at a star and see a red color light being emmited from the star. This basically means the star is traveling in the direction of the person viewing it. This person could also see another star and see a blue color light being emmited from the star. This simply means the star in traveling away from the person viewing it.

Also, of course the size could be different based on how close the star is. We know all stars are extremely far away from earth but you can tell if a star is closer to earth than another star based on if it is relatively larger than than other star and if it is brighter. To John, the star he sees has a blue light so his star is traveling away from him. However, to Jane her star has a red light which means that star is traveling towards the earth. To summarize, Jane's star has a red light and is traveling towards the earth while John's star star has a blue light and is traveling away from the earth. This is also a prime example of the Doppler Effect in motion. The stars look different because they are traveling in different directions.

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Two uniform, solid cylinders of radius R and total mass M are connected along their common axis by a short, light rod and rest o

sveta [45]

Explanation:

A) To prove the motion of the center of mass of the cylinders is simple harmonic:

System diagram for given situation is shown in attached Fig. 1

We can prove the motion of the center of mass of the cylinders is simple harmonic if

$a_{x} = -\omega^{2} x$

where aₓ is acceleration when attached cylinders move in horizontal direction:

<h3>PROOF:</h3>

rotational inertia for cylinders is given as:

$I=\frac{1}{2}MR^{2}$ -----(1)

Newton's second law for angular motion is:

∑τ = Iα ------(2)

For linear motion in horizontal direction it is:

∑Fₓ = Maₓ ------ (3)

By definition of torque:

τ = RF --------(4)

Put (4) and (1) in (2)

$RF=\frac{1}{2}MR^{2}\alpha$

from Fig 3 it can be seen that fs is force by which the cylinders roll without slipping as they oscillate

So above equation becomes

$f_{s}=\frac{1}{2}MR\alpha$ ------ (5)

As angular acceleration is related to linear by:

$a= R\alpha$

Eq (5) becomes

$f_{s}=\frac{1}{2}Ma_{x}$ ---- (6)

aₓ shows displacement in horizontal direction

From (3)

∑Fₓ = Maₓ

Fₓ is sum of fs and restoring force that spring exerts:

$\sum F_{x} = f_{s} - kx$ ----(7)

Put (7) in (3)

$f_{s} - kx = Ma_{x}$ [/tex] -----(8)

Using (6) in (8)

$\frac{1}{2}Ma_{x} - kx =Ma_{x}$

$a_{x} = \frac{2k}{3M} x$ --- (9)

For spring mass system

$a= -\omega^{2} x$ ----- (10)

Equating (9) and (10)

$\omega^{2} = \frac{2k}{3M}$

$\omega = \sqrt{ \frac{2k}{3M}}$

then (9) becomes

$a_{x} = - \omega^{2}x$

(The minus sign says that x and aₓ have opposite directions as shown in fig 3)

This proves that the motion of the center of mass of the cylinders is simple harmonic.

<h3 /><h3>B) Time Period</h3>

Time period is related to angular frequency as:

$T=\frac{2\pi }{\omega}$

$T = 2\pi \sqrt{\frac{3M}{2k}$

5 0

2 years ago

Weight is measured in units called

Aleksandr-060686 [28]

Pounds

If you are talking about the unit of measurement for weight is that of force it would be Newtons.

8 0

2 years ago

A spherical snowball melts at a rate proportional to its surface area. (a) write a differential equation for its volume, v. (use

tresset_1 [31]

Answer:

Explanation:

The rate of change in volume is proportional to the surface area:

dV/dt = kA

Integrating:

V = kAt + C

At t=0, V = s, so:

s = kA(0) + C

C = s

Therefore:

V = kAt + s

6 0

2 years ago

Someone please help with these 2

Ann [662]

Answer:

Explanation:

The formula that you are working with is F = m*a

Since mass is one part of the formula if you increase the mass, you are going to increase the force.

The second one is much more difficult to answer because it is basically incomplete. This is one way to interpret it. If you start at a certain speed and increase during a known time period then effectively you are defining acceleration which is "a" in the formula.

Without those modifications, there is no answer.

6 0

1 year ago

If a radio wave carries information by changing the amplitude of the transmitted wave, what kind of broadcast might it possibly

mariarad [96]

Option A because those are the correct ones

4 0

1 year ago