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3 years ago

What kind of atmospheric pressure does Makemake have?

Physics

1 answer:

SSSSS [86.1K]3 years ago

4 0

Answer:

Explanation:

dwarf planet is closer to the Sun in its orbit, it probably warms up. And methane and ethane are gases then, and form an atmosphere.

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What is the product of nuclear fission?

RideAnS [48]

Nuclear fission is seperating an atom so product is b.

Energy is released during nuclear fussion. Mass is converted into energy because E=mc^2, this is the energy that is released

5 0

3 years ago

A cylindrical, 0.500-m rod has a diameter of 0.02 m. The rod is stretched to a length of 0.501 m by a force of 3000 N. What is t

Salsk061 [2.6K]

Answer:

Y = 4.775 x 10⁹ Pa = 4.775 GPa

Explanation:

First, we calculate the stress on the rod:

$stress = \frac{Force}{Area} = \frac{3000\ N}{\pi r^2} \\\\stress = \frac{3000\ N}{\pi (0.01\ m)^2}\\\\stress = 9.55\ x\ 10^6\ Pa = 9.55 MPa\\$

Now, we calculate the strain:

$strain = \frac{Change\ in Length}{Original\ Length}\\\\strain = \frac{0.501\ m - 0.5\ m}{0.5\ m}\\\\strain = 0.002\\$

Now, we will calculate the Young's Modulus (Y):

$Y = \frac{stress}{strain}\\\\Y = \frac{9.55\ x\ 10^6\ Pa}{0.002} \\$

6 0

3 years ago

How is a ecosysten different from a community

Komok [63]

An ecosystem is the diversity of many communities of organisms where they interact with living as well as non living thing whereas community contains the variety of populations of different species. Hope this helps x

5 0

3 years ago

Read 2 more answers

Water towers store water above the level of consumers for times of heavy use, eliminating the need for high-speed pumps. How hig

Salsk061 [2.6K]

Answer:

So height will be 47.387 m

Explanation:

We have given gauge pressure $P=4.63\times 10^5N/m^2$

Density of water $\rho =997kg/m^3$

Acceleration due to gravity $g=9.8m/sec^2$

We know that pressure is given as $P=\rho gh$

$4.63\times 10^5=997\times 9.8\times h$

$h=47.387m$

So height will be 47.387 m

4 0

3 years ago

(1 point) A frictionless spring with a 3-kg mass can be held stretched 1.6 meters beyond its natural length by a force of 90 new

Nonamiya [84]

Answer:

x(t)=0.337sin((5.929t)

Explanation:

A frictionless spring with a 3-kg mass can be held stretched 1.6 meters beyond its natural length by a force of 90 newtons. If the spring begins at its equilibrium position, but a push gives it an initial velocity of 2 m/sec, find the position of the mass after t seconds.

Solution. Let x(t) denote the position of the mass at time t. Then x satisfies the differential equation

$m \frac{d^{2}x}{dt^{2}} +kx=0$

Definition of parameters

m=mass 3kg

k=force constant

e=extension ,m

ω =angular frequency

k=90/1.6=56.25N/m

ω^2=k/m= 56.25/1.6

ω^2=35.15625

ω=5.929

General solution will be

$x(t)=c1cos(ωt)+c2Sin(ωt)$

$x(t)=c1cos(5.929t)+c2Sin(5.929t)$

differentiating x(t)

dx(t)=-5.929c1sin(5.929t)+5.929c2cos(5.929t)

when x(0)=0, gives c1=0

dx(t0)=2m/s gives c2=0.337

Therefore, the position of the mass after t seconds is

x(t)=0.337sin((5.929t)

6 0

3 years ago