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Vsevolod [243]
3 years ago
14

Suppose that a laboratory analysis of white powder showed 42.59% Na, 12.02% C, and 44.99% oxygen. Would you report that the comp

ound is sodium oxalate or sodium carbonate? (Use 43.38% Na, 11.33% C, and 45.29% O for sodium carbonate, and 34.31% Na, 17.93% C, and 47.76% O for sodium oxalate.)
Chemistry
1 answer:
butalik [34]3 years ago
8 0

Answer:

The white powder is sodium carbonate

Explanation:

If you supposed an ammount of 100 grams of the white powder,  it means there are 42.59 grams of Na, 12.02 grams of C and 44.99 grams of O. If you divided every compound by its molar mass, you will know the moles of every compound. (According to moles=mass (grams)/ molar mass (grams/mole)

C=12.01 g/mole, Na=23 g/mole, O=16 g/mole

So:

C=12.02/12.01= 1.0 moles, Na=42.59/ 23= 1.85 moles, O= 44.99/16= 2.81 moles

Knowing this, we can stimated that the white powder has 1 mol of C and approximately 2 and 3 moles of N and O, respectively

Chemical formula for sodium carbonate is Na2CO3 and the formula for sodium oxalate is Na2C2O4. So the white powder is Na2CO3

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alukav5142 [94]

Answer: The correct option is 2.

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5 0
3 years ago
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What factors mechanical weathering ?. <br><br><br> Earth Science.
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Answer:

-Growth of plants on the rock.

-Temperature and pressure changes in nature.

-Freezing and thawing of water in cracks of the rock.

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-Burrowing by animals.

those are some factors I know

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Which one is you fav one
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What pressure will be exerted by 25 g of CO2 at temperature of 25°C and a volume of .50 L?
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Answer:

P = 27.9 atm

Explanation:

Given data:

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Volume of gas = 0.50 L

Pressure of gas = ?

Solution:

Firs of all we will calculate the number of moles of gas,

Number of moles = mass/molar mass

Number of moles = 25 g/ 44 g/mol

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Pressure of gas :

PV = nRT

P= Pressure

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n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

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P × 0.50 L = 0.57 mol × 0.0821 atm.L/ mol.K  × 298.15 K

P = 13.95 atm.L/ 0.50 L

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4 0
3 years ago
How many grams of aluminum chloride are needed to react completely with 1.084g lithium sulfide?
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Molar mass :

Li₂S = <span>45.947 g/mol

AlCl</span>₃ = <span>133.34 g/mol

</span><span>3 Li</span>₂<span>S + 2 AlCl</span>₃<span> = 6 LiCl + Al</span>₂S₃

3 * 45.947 g Li₂S ----------> 2 * <span>133.34 g AlCl</span>₃
1.084 g Li₂S ----------------> ?

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Mass Li₂S = 289.08112 / 137.841

Mass Li₂S = 2.0972 g 

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