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muminat
3 years ago
10

Which item is made from an alloy? A. steel tray B. glass plate C. credit card D. copper wire

Chemistry
2 answers:
Naya [18.7K]3 years ago
6 0

Not sure if this is correct but i would choose the steel tray.

Anna007 [38]3 years ago
4 0

It's A).steel tray because steel is an <u>iron-carbon alloy</u>.


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What is the balanced form of the following equation?. Br2 + S2O32– + H2O → Br1– + SO42– + H+.
zloy xaker [14]
For the equation to be balanced, the Atom's coefficient on the left side and the right side of the equation has to be equal

so, the answer would be : 

Br2 + S2032- + 5H20 -- >  BR2- + 2S02- + H+

Hope this helps
8 0
3 years ago
Argon (Ar) and helium (He) are initially in separate compartments of a container at 25°C. The
love history [14]

Answer:

(a) V_B=11.68L

(b) x_{He}=0.533

Explanation:

Hello,

In this case, since the both gases behave ideally, with the given information we can compute the moles of He in A:

n_A=\frac{0.082\frac{atm*L}{mol*K}*298K}{1.974 atm*6.00L}=2.063mol

Thus, since the final pressure is 3.60 bar, we can write:

P=x_{Ar}P_A+x_{He}P_B\\\\P=\frac{n_{Ar}}{n_{Ar}+n_{He}} P_A+\frac{n_{He}}{n_{Ar}+n_{He}} P_B\\\\3.60bar=\frac{2.063mol}{2.063mol+n_{He}} *2.00bar+\frac{n_{He}}{2.063mol+n_{He}} *5.00bar

The moles of helium could be computed via solver as:

n_{He}=2.358mol

Or algebraically:

3.60bar=\frac{1}{2.063mol+n_{He}} *(4.0126+5.00*n_{He})\\\\7.314+3.60n_{He}=4.013+5.00*n_{He}\\\\7.314-4.013=5.00*n_{He}-3.60n_{He}\\\\n_{He}=\frac{3.3}{1.4}=2.358mol

In such a way, the volume of the compartment B is:

V_B=\frac{n_{He}RT}{P_B}=\frac{2.358mol*0.082\frac{atm*L}{mol*K}*298.15K}{4.935atm}\\  \\V_B=11.68L

Finally, he mole fraction of He is:

x_{He}=\frac{2.358}{2.358+2.063}\\ \\x_{He}=0.533

Regards.

8 0
3 years ago
Calculate the ph of a solution formed by mixing 200.0 ml of 0.30 m hclo with 300.0 ml of 0.20 m kclo. the ka for hclo is 2.9 × 1
masha68 [24]

Answer:

The pH of the solution will be 7.53.

Explanation:

Dissociation constant of KClO=K_a=2.8\times 10^{-8}

Concentration of acid in 1 l= 0.30 M

Then in 200 ml = 0.30 M\times 0.200 L=0.06 M

The concentration of acid, HClO=[acid]= 0.006 M

Concentration of salt in 1 L = 0.20 M

Then in 300 ml = 0.20 M\times 0.300 L=0.06 M

The concentration of acid, KClO=[salt]= 0.006 M

The pH of the solution will be given by formula :

pH=pK_{a}^o+\log\frac{[salt]}{[acid]}

pH=-\log[2.8\times 10^{-8}]+\frac{[0.06 M]}{[0.06 M]}

The pH of the solution will be 7.53.

4 0
3 years ago
Read 2 more answers
Which of the following radiations consists of a helium nucleus emitted by some radioactive substances? Alpha radiation Beta radi
erica [24]

Answer: Alpha radiation

Explanation: Alpha decay : When a larger radioactive nuclei decays into smaller nuclei by releasing alpha radiation, the mass number and atomic number is reduced by 4 and 2 units respectively.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}Y+_2^4\textrm{He}


Beta decay : When a larger radioactive nuclei decays into smaller nuclei by releasing beta radiation, the atomic number is increased by 1 unit.


_Z^A\textrm{X}\rightarrow _{Z+1}^{A}Y+_{-1}^0e


Gamma decay : When a larger radioactive nuclei decays into smaller nuclei by releasing gamma radiation, the mass number remains same.

_Z^A\textrm{X}^*\rightarrow _Z^A\textrm{X}+_0^0\gamma

5 0
3 years ago
What is the maximum number of electrons possible in a set of 5f orbitals?
TiliK225 [7]
The answer is 14.

Hope this helps
3 0
3 years ago
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