Ask question

Ask question

All categories

GarryVolchara [31]

3 years ago

14

A drawn or written record of star groups in the night sky are called

2 answers:

skelet666 [1.2K]3 years ago

4 0

Answer: A constellations

Explanation: hope it helps

Crazy boy [7]3 years ago

4 0

Answer:

A) Constellations

Explanation:

A constellation are a group of stars appears to form a pattern or picutures.

You might be interested in

When the drivers pass each other, the driver of the red car is to toss a package of contraband to the other driver. To catch the

Brrunno [24]

Answer:

D=387.28m

Explanation:

At the moment where the toss is made $X_R = X_G$ , so we need both equations:

For the red car:

$X_R=\frac{a_R*t^2}{2}$ With initial speed of 0 and acceleration of 6.12m/s^2.

For the green car:

$X_G=Xo + V_G*t$ With $V_G = 60km/h*\frac{1000m}{1km} * \frac{1h}{3600s} = 16.66m/s$ and Xo = 200m

Since both positions will be the same:

$\frac{a_R*t^2}{2}=Xo+V_G*t$ Solving for t:

t1 = -5.8s and t1 =11.25s

Replacing t = 11.25 on either equation to find the displacement:

$D = X_R = \frac{a_R*t^2}{2} = 387.28m$

3 0

4 years ago

Choose all the answers that apply. Which of the following forces require physical contact? tension, air resistance, friction, ma

svet-max [94.6K]

Answer:

I belive it would be friction applied force and tension

Explanation:

8 0

4 years ago

Marvin uses a long copper wire with resistivity 1.68 x 10^-8 Ω⋅m and diameter 1.00 x 10^−3 m to create a solenoid that has a 3

Mazyrski [523]

Answer with Explanation:

We are given that

Resistivity of copper wire= $\rh0=1.68\times 10^{-8}\Omega m$

Diameter=d= $1.00\times 10^{-3} m$

Radius of copper wire= $r=\frac{d}{2}=\frac{1}{2}\times 10^{-3} m$

Radius of solenoid=r' $=3 cm=3\times 10^{-2} m$

1 m=100 cm

a.Length of wire=l=11.3 m

Area of wire=A= $\pi r^2$

Where $\pi=3.14$

A= $3.14\times (\frac{1}{2}\times 10^{-3})^2$

Resistance, R= $\rho \frac{l}{A}$

Using the formula

$R=1.68\times 10^{-8}\times\frac{11.3}{3.14\times (\frac{1}{2}\times 10^{-3})^2}$

$R=0.24\Omega$

B.Length of solenoid= $2\pi r'=2\times 3.14\times 3\times 10^{-2}=0.188$ m

Number of turns= $n_0=\frac{l}{2\pi r'}=\frac{11.3}{0.188}$

$n_0$ =60

C.Potential difference,V=3 V

Current,I= $\frac{V}{R}$

I= $\frac{3}{0.24}=12.5 A$

D.Total length =0.1 m

Number of turns per unit length,n= $\frac{60}{0.1}=600$

Magnetic field along central axis inside of the solenoid,B= $\mu_0 nI$

$B=4\pi\times 10^{-7}\times 12.5\times 600=9.42\times 10^{-3} T$

4 0

3 years ago

Read 2 more answers

Briefly describe the Rutherford atomic model

cricket20 [7]

Answer:

The Rutherford model was made by Ernest Rutherford, to describe a atom. That is a brief explanation

Explanation:

6 0

3 years ago

A 48.5 kg student runs down the sidewalk and jumps with a horizontal speed of 4.25 m/s onto a stationary skateboard. The student

storchak [24]

<u>Answer:</u>

2.39 kg

<u>Explanation:</u>

There is conservation of momentum here in this problem so we will use the following problem:

$m_1u_1+m_2u_2=(m_1+m_2)v$

where the mass of the student $m_1$ is 48.5 kg,

the mass of the skateboard $m_2$ is $m_2$ kg,

the initial speed of the student $u_1$ is 4.25 m/s; and

the speed of the student and skateboard $v$ is 4.05 m/s.

So substituting the given values in the above formula to get:

$(48.5*4.25) + (m_2 * 0) = (48.5 + m_2 ) * 4.05$

$206.125=196.425+4.05m_2$

$206.125 - 196.425 = 4.05m_2$

$m_2=\frac{9.7}{4.05}$

$m_2=2.39$

Therefore, the mass of the skateboard is 2.39 kg.

7 0

3 years ago