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Ilya [14]
3 years ago
7

A piece of amber is charged by rubbing with a piece of fur. If the net excess charge on the fur is 8.9 nC ( 8.9 10-9 C), how man

y electrons were added to the amber
Physics
1 answer:
Alika [10]3 years ago
7 0

Answer:

Number of electrons, n=5.56\times 10^{10}

Explanation:

Given that,

Charge on the fur, q=8.9\ nC=8.9\times 10^{-9}\ C

A piece of amber is charged by rubbing with a piece of fur. We need to find the electrons were added to the amber. It can be calculated using the quantization of charge as

q = n × e

Where

n is the number of electrons

e is the charge on electron

n=\dfrac{q}{e}

n=\dfrac{8.9\times 10^{-9}}{1.6\times 10^{-19}}

n=5.56\times 10^{10}\ electrons

So, n=5.56\times 10^{10}\ electrons number of electrons are added to the amber. Therefore, this is the required solution.

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A girl swings on a playground swing in such a way that at her highest point she is 4.1 m from the ground, while at her lowest po
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Answer:

V1 =8.1 m/s

Explanation:

height at highest point (h2) = 4.1 m

height at lowest point (h1) = 0.8 m

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from conservation of energy, the total energy at the lowest point will be the same as the total energy at the highest point. therefore

mgh1 + 0.5mV1^{2} = mgh2 + 0.5mV2^{2}

where

  • speed at highest point = V2
  • speed at lowest point = V1
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  • at the highest point, the  speed is minimum (V1 = 0)
  • at the lowest point the speed is maximum (V2 is the maximum speed)
  • therefore the equation becomes mgh1 + 0.5mV1^{2} = mgh2

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now we can substitute all required values into the equation above.

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Answer:

The answer to the question is;

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B   >→   A   >→    E   >→    C    >→     F    >→     D.

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Satellite F)       \frac{80^2}{10000}  = 0.64 m/s²

Therefore in order of decreasing acceleration, from largest to smallest we have

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