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Tatiana [17]
1 year ago
15

If the volume of a gaseous system is increased by a factor of 3 and the temperature is raised by a factor of 6, then the pressur

e of the system will.
Physics
1 answer:
N76 [4]1 year ago
8 0

A gaseous system's pressure will rise by a factor of 2 if its volume is increased by a factor of 3 and its temperature is raised by a factor of 6.

<h3>What do you mean by pressure?</h3>

The stress at a location within a confined fluid or the perpendicular force per unit area are the two definitions of pressure used in the physical sciences. A surface will be subject to pressure from a 42-pound box with a bottom area of 84 square inches equivalent to half a pound per square inch of applied force. The weight of the atmosphere pressing down on each square inch of the Earth's surface is known as atmospheric pressure, which is approximately 15 pounds per square inch at sea level. In SI units, pressure is expressed in Pascals.

To know more about pressure, visit:

brainly.com/question/12971272

#SPJ4

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This is 100 points. When i find out how i will put the first person to answer as brainiest.
grin007 [14]

Answer:

Thank you so much! Have a great day!

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2 years ago
Differentiate between atmospheric pressure and pressure.​
Dovator [93]

Answer: atmospheric is air by the earth and pressure is just someone or something doing it

Explanation:

8 0
3 years ago
Read 2 more answers
I need homework help
KIM [24]
1) the weight of an object at Earth's surface is given by F=mg, where m is the mass of the object and g=9.81 m/s^2 is the gravitational acceleration at Earth's surface. The book in this problem has a mass of m=2.2 kg, therefore its weight is 
F=mg=(2.2 kg)(9.81 m/s^2)=21.6 N

2) On Mars, the value of the gravitational acceleration is different:g=3.7 m/s^2. The formula to calculate the weight of the object on Mars is still the same, but we have to use this value of g instead of the one on Earth: F=mg=(2.2 kg)(3.7 m/s^2)=8.1 N

3) The weight of the textbook on Venus is F=19.6 N. We already know its mass (m=2.2 kg), therefore by re-arranging the usual equation F=mg, we can find the value of the gravitational acceleration g on Venus: 
g= \frac{F}{m}= \frac{ 19.6 N}{2.2 kg}=8.9 m/s^2

4) The mass of the pair of running shoes is m=0.5 kg. Their weight is F=11.55 N, therefore we can find the value of the gravitational acceleration g on Jupiter by re-arranging the usual equation F=mg: 
g= \frac{F}{m} = \frac{11.55 N}{0.5 kg} =23.1 m/s^2

5) The weight of the pair of shoes of m=0.5 kg on Pluto is F=0.3 N. As in the previous step, we can calculate the strength of the gravity g on Pluto as 
g= \frac{F}{m} = \frac{0.3 N}{0.5 kg} =0.6 m/s^2

<span>6) On Earth, the gravity acceleration is </span>g=9.81 m/s^2<span>. The mass of the pair of shoes is m=0.5 kg, therefore their weight on Earth is 
</span>F=mg=(0.5 kg)(9.81 m/s^2)=4.9 N<span>
</span>
5 0
3 years ago
One of the element carbon combines with one of the element oxygen to form one of the compound carbon dioxide.
saul85 [17]
False. C + O --> CO not CO2. Carbonmonoxide
3 0
3 years ago
Read 2 more answers
A 4.0 Ω resistor has a current of 3.0 A in it for 5.0 min. How many electrons pass 3. through the resistor during this time inte
musickatia [10]

Answer:

Number of electrons, n=5.62\times 10^{21}

Explanation:

It is given that,

Resistance, R = 4 ohms

Current, I = 3 A

Time, t = 5 min = 300 s

We need to find the number of electrons pass through the resistor during this time interval. Let the number of electron is n.

i.e. q = n e ...............(1)

And current, I=\dfrac{q}{t}

I\times t=n\times e

n=\dfrac{It}{e}

e is the charge of an electron

n=\dfrac{3\ A\times 300\ s}{1.6\times 10^{-19}}

n=5.62\times 10^{21}

So, the number of electrons pass through the resistor is 5.62\times 10^{21}. Hence, this is the required solution.

6 0
3 years ago
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