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Neko [114]
2 years ago
13

What is the size of the smallest vertical plane mirror in which a 6 ft tall person standing erect can see her full-length image?

Physics
1 answer:
Alex Ar [27]2 years ago
5 0

Answer:

3 ft

..................

You might be interested in
Why is it important for coastal areas exposed to destructive forces to be aware of the effects of these forces?
Fantom [35]

Answer:

the answer should be in the explanation

Explanation:

Volcanic Eruption

Cracks in the earth’s crust are called faults. Volcanoes and earthquakes usually occur along these faults. A volcanic eruption can lead to landslides, ash falls, mud-flows, pyroclastic flows (can burn everything in their way), and steam explosions. okay for example volcanoes people have to keep a close eye out when they live by an active search up valcanic damage and you will see what i mean

6 0
2 years ago
What is the resultant of 5N force pointing north and 7N force pointing south? Do not forget include direction
balandron [24]

Given forceF

1

=5N and F

2

=7N and θ=60

We know resultant force F=

5

2

+7

2

+2(5)(7)cos60

F=

25+49+35

F=

109

it's your answer

4 0
3 years ago
A round loop of wire carries a current of 100 A, has a radius of 10 cm, and its normal (vector) makes an angle of 30∘ with a mag
Oliga [24]

Answer:

0.823 Nm

Explanation:

current, i = 100 A

radius, r = 10 cm

Angle between the normal and the magnetic field, θ = 30°

Magnetic field, B = 0.524 T

Torque is defined as the

\tau = i \times A\ B\times sin\theta

\tau = 100 \times 3.14\times 0.1\times 0.1\ 0.524\times 0.5

Torque = 0.823 Nm

Thus, the torque is 0.823 Nm.

7 0
3 years ago
A 2,294N force is applied to a 408kg mass. What is the acceleration of the mass?
Nataly_w [17]

Answer:

5.622

Explanation:

a=F/M

a=2294/408

a=5.622

8 0
3 years ago
A speed skater moving across frictionless ice at 9.2 m/s hits a 5.0 m wide patch of rough ice. She slows steadily, then continue
enot [183]

Answer:

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

Explanation:

The distance travelled on the rough ice is equal to the width of the rough ice.

distance d = 5.0 m

Initial speed u = 9.2 m/s

Final speed v = 5.8 m/s

The time taken to move through the rough ice can be calculated using the equation of motion;

d = 0.5(u+v)t

time t = 2d/(u+v)

Substituting the given values;

t = 2(5)/(9.2+5.8)

t = 2/3 = 0.66667 second

The acceleration is the change in velocity per unit time;

acceleration a = ∆v/t

a = (v-u)/t

Substituting the values;

a = (5.8-9.2)/0.66667

a = -5.099974500127

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

7 0
3 years ago
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