Answer:
b. is the process in which two smaller nuclei combine to form a larger nucleus
Answer:
29865.31 m/s
Explanation:
Radius of the Earth orbit if it is assumed to be circular = 1.5×10¹¹ m = r
<em>Circumference of the orbit = 2πr</em>
<em>= 2π×1.5×10¹¹</em>
<em>= 3π×10¹¹ m</em>
Time taken by Earth to complete one rotation around the orbit = 365.25 days
<em>Converting to seconds we get</em>
<em>365.25×24×60×60</em>
<em>= 31557600 seconds</em>
Velocity of Earth
∴ The average speed of Earth in its orbit is 29865.31 m/s
According to the rules for significant figures, simple decimal subtraction is done. But since 15.54 is only accurate to the hundredths place, then the resulting difference should also be rounded off to the nearest hundredths. This is shown below:
508.9538 - 15.54 = 493.4138
Rounding off to the nearest hundredths:
= 493.41
Force = 3200 N
Work done = 640, 000 Nm
Explanation:
We begin by calculating the deceleration of the truck, using the velocity and distance;
a = (v² – u²)/2s
whereby;
a = acceleration
v = initial velocity
u = initial velocity
s = distance
We begin by changing the speed from km/h into m/s;
54km/hr = 15m/s
Then acceleration;
a = (0² – 15²) / 2 * 200
a = -225 / 400
a = - 0.5625 m/ s²
To calculate force;
F = ma
Whereby;
F = force
M = mass (in kgs)
a = acceleration
F = 1800 / 0.5625
F = 3200 N
Work done = Force * displacement
Work done = 3200 * 200
= 640, 000 Nm
Learn More:
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