Answer:
About 2 units.
Explanation:
We assume that there is no heat dissipating instrument in the room
Total cooling load of the room is defined from the given below equation
=++
where
= 10*100 W =1 KW
= 40*360 KJ/h= 4 KW
=15000KJ/h= 4.17 KW
= 1+4+4.17=9.17 KW
the number of air conditioner unit is ==1.83
which is approximately 2 units
Answer:
transition metals im sorry if this was too late
The magnification formula is:
M = H (i)/H (o) = -D (i)/D (o)
In other words, the ratio of the image distance and object distance to the ratio of the image height and the object height.
Disk of dust and gas contains the new born stars and as well as young stars and the Halo region contains the old stars.
The different regions of a spiral galaxy like our Milky way tend to have characteristic populations of stars.
Halo: The halo tends to have older, red stars. In general, blue stars are larger but since they are also hotter, tend to run through their fuel faster and have shorter lives. Halo stars tend to be older stars, The halo is generally lacking in dust and low in metals.
Bulge: The outer Area of the bulge has mostly older red stars. The inner bulge has active star formation and has a mix of red and blue stars.
Disk: The disk has active star formation regions, so there are young blue stars in that region. Here are the stars that are both old stars and young stars. The blue stars are largely found on the edges of the spiral arms.
Thus disk with the dust clouds contains new and young stars. And halo region contains old stars.
#SPJ4
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