To thaw a product requires it to undergo the process of
being subjected to latent heat of fusion. In this process, there is no change
in temperature however there is a change of phase from solid to liquid. What is
being thawed here actually is the frozen ice into liquid water which is in the
vegetables.
From the references, the latent heat of fusion of water
is:
Δ H = 333.55 kJ / kg
Therefore the amount of heat required to thaw the frozen
vegetable is:
Heat required = Δ H * m
Heat required = (333.55 kJ / kg) (0.450 kg)
Heat required = 150.10 kJ
In 1 kcal there is 4.184 kJ, therefore:
Heat required = 150.10 kJ (1 kcal / 4.184 kJ)
<span>Heat required = 35.87 kcal</span>
Answer:
Hello your question is incomplete attached below is the complete question
answer : ri ( thickness of wire ) = 14.167 m
Explanation:
attached below is a detailed solution
using the given data to determine the thickness of wire
The charge<span> of that </span>atom<span> is +1</span>
Answer:
Given mass = 2kg, height = 1.2m,g = 9.8.
We know that Work done W = FD
= > W = (mg)(D)
= > W = (2 * 9.8)(1.2)
= > W = 23.52 Joules.