Answer : The molar mass of catalase is, 
Explanation :
Formula used :
where,
= osmotic pressure = 0.745 torr = 0.000980 atm (1 atm = 760 torr)
C = concentration
R = solution constant = 0.0821 L.atm/mol.K
T = temperature = 
w = mass of catalase = 10.03 g
M = molar mass of catalase = ?
V = volume of solution = 1.05 L
Now put all the given values in the above formula, we get:
Therefore, the molar mass of catalase is,
The solution would be like
this for this specific problem:
<span>25.0 g CCl4 x (1 mole CCl4
/ 153.8 g CCl4) = 0.163 moles CCl4
</span>(29.82 kJ / mole)(0.163 moles) = 4.86 kJ
total heat = 1.11 kJ + 4.86 kJ = 5.97 kJ
<span>I hope this helps and if you have
any further questions, please don’t hesitate to ask again. </span>
Explanation:
To solve this problem, we simply use the periodic table of elements which groups elements based on their atomic numbers.
The atomic number of an element is the number of protons it contains. The protons are the positively charged particles within an atom.
- The vertical arrangement of elements on the periodic table is the group.
- The horizontal arrangement of elements is the period.
Now;
Noble gases belongs to group 18
Alkali earth metals belongs to group 2
Halogens belongs to group 17
Alkali metals belongs to group 1
Transition metals belongs to group 3-12
