Answer:
Let the mixture is X% by mass of CuSO
4
.5H
2
O and 100 - X % by mass of MgSO
4
.7H
2
O. 5.0 g of mixture will contain 0.05X g CuSO
4
.5H
2
O and 5.0 - 0.05X g MgSO
4
.7H
2
O
The molar masses of CuSO
4
.5H
2
O and MgSO
4
.7H
2
O are 249.7 g/mol and 246.5 g/mol respectively.
The number of moles of CuSO
4
.5H
2
O=
249.7
0.05X
=2.00×10
−4
X moles.
Explanation:
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<h2>second</h2>
<h2>hop this may help you</h2>
Answer:
1. For the first reaction, there is Carbonation and rearrangement
2. For the second reaction, No Carbonation, No rearrangement.
Explanation:
See attached screenshot below
Answer:
When you heat an atom, some of its electrons are "excited* to higher energy levels. When an electron drops from one level to a lower energy level, it emits a quantum of energy. ... The different mix of energy differences for each atom produces different colours. Each metal gives a characteristic flame emission spectrum.
Explanation:
The mass of chlorine required to react with 10.0 g of sodium metal to produce sodium chloride is 15.26 g.
The balanced chemical reaction is :
<em> 2Na + Cl₂ → 2NaCl</em>
<em />
Given data :
Mass of sodium = 10.0 g
Number of moles of Na -
Number of moles = <u> Given mass </u>
Molar mass
Number of moles = <u> 10.0 g</u> = 0.43 mol
23 g
Comparing moles of Na and Cl₂ from the balanced chemical equation,
Na : Cl₂
2 : 1
0.43 : <u> 1 </u> x 0.43 = 0.215 mol
2
Mass of chlorine gas :
(molar mass of chlorine = 71 g)
Mass of chlorine = number of moles x molar mass
Mass = 0.215 mol x 71 g/mol
= 15.26 g
To learn more about sodium and chlorine,
brainly.com/question/14588368
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