1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GrogVix [38]
3 years ago
15

-

Chemistry
1 answer:
mart [117]3 years ago
3 0

Answer:

reaction B is the best one I would choose

You might be interested in
A sample of potassium chlorate (15.0 g) is dissolved in 201 g of water at 70 °c with precautions taken to avoid evaporation of a
zlopas [31]
Answer is: unsaturated.
Solubility of potassium chlorate on 70°C is approximately 30 grams in 100 grams of water.
Solubility of potassium chlorate on 70°C is approximately 10 grams in 100 grams of water.
So if dissolve 15 g of potassium chlorate in 201 g of water, there is less salt than it solubility and solution is unsaturated.
4 0
3 years ago
Please help!! Why is the following Electron Configuration incorrect for Aluminium?
Margarita [4]

Answer:

3s^1 would be 3s^2

Explanation:

5 0
3 years ago
The electrons in the outer shell of an atom are called:<br> outer<br> ionized<br> polar<br> valence
Marrrta [24]
Valence.

The electrons in the outer shell of an atom are called valence electrons. 

Valence electrons determine whether the an element is ready form compounds. These electrons can be gained, lost, or shared in the formation of compounds.
7 0
3 years ago
Write a reaction to describe the behavior of the following substances in water. please include all phases.
lorasvet [3.4K]

3NF3 + 5H2O → HNO3 + 2NO + 9HF

Nitrogen fluoride reacts with water to produce nitric acid, nitric oxide, and hydrogen fluoride. The reaction slowly takes place in a boiling solution.

CH2CH2 + H2O → CH3CH2OH

Ethylene is a hydrocarbon with water that creates ethanol and ethanol is an alcohol

4 0
3 years ago
How many moles are in 39.5 grams of Lithium?
Blizzard [7]

Answer:

185.05 g.

Explanation

Firstly, It is considered as a stichiometry problem.

From the balanced equation: 2LiCl → 2Li + Cl₂

It is clear that the stichiometry shows that 2.0 moles of LiCl is decomposed to give 2.0 moles of Li metal and 1.0 moles of Cl₂, which means that the molar ratio of LiCl : Li is (1.0 : 1.0) ratio.

We must convert the grams of Li metal (30.3 g) to moles (n = mass/atomic mass), atomic mass of Li = 6.941 g/mole.

n = (30.3 g) / (6.941 g/mole) = 4.365 moles.

Now, we can get the number of moles of LiCl that is needed to produce 4.365 moles of Li metal.

Using cross multiplication:

2.0 moles of LiCl → 2.0 moles of Li, from the stichiometry of the balanced equation.

??? moles of LiCl → 4.365  moles of Li.

The number of moles of LiCl that will produce 4.365 moles of Li (30.3 g) is (2.0 x 4.365 / 2.0) = 4.365 moles.

Finally, we should convert the number of moles of LiCl into grams (n = mass/molar mass).

Molar mass of LiCl = 42.394 g/mole.

mass = n x molar mass = (4.365 x 42.394) = 185.05 g.

7 0
2 years ago
Read 2 more answers
Other questions:
  • Based on the mole ratios, what can most likely be predicted?
    14·1 answer
  • Assume an object A mass of 36.240 g and it’s density is 5.40 g/mL. What is it’s volume
    8·1 answer
  • In the compound KHSO4, there is an ionic bond between the
    11·1 answer
  • Consider the following general voltaic cell and a cell notation, and answer all three parts of this question.
    9·1 answer
  • How do Earth's lithosphere,hydrosphere,and atmosphere compare?
    11·2 answers
  • Which statement best explains why Earth's outer core is in liquid form?
    11·2 answers
  • A flask contains methane, chlorine, and carbon monoxide gases. The partial pressures of each are 0.215 atm, 50 torr, and 0.826 r
    7·1 answer
  • How many protons, neutrons and electrons are in these atoms?
    5·1 answer
  • Please help on question 7 and 8<br>​
    12·1 answer
  • Calculate the molecular mass of the element
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!