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daser333 [38]
3 years ago
7

1.Salts consist of atomic particles that have an (blank) charge.

Chemistry
1 answer:
enyata [817]3 years ago
5 0
The nonmetal elements have a negative charge.
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What is the electron configuration for<br> 08<br> 16
Elis [28]

The electron configuration for Oxygen : [He] 2s²2p⁴

<h3>Further explanation</h3>

Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub-shells in the shell of an atom, namely s, p, d, and f. The maximum number of electrons for each sub-shell is  

• s: 2 electrons  

• p: 6 electrons  

• d: 10 electrons and  

• f: 14 electrons  

Charging electrons in the sub-shell uses the following sequence:  

<em>1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.  </em>

The element is Oxgen, with symbol O, and :

the atomic number=8=number of electron

the atomic mass=16

The electron configuration based on the number of electrons(for Oxygen=8), so the configuration :

\tt _8^{16}O:1s^22s^22p^4 or we can write with noble gas [He] 2s²2p⁴

3 0
2 years ago
Alguien sabe el nombre del compuesto etilisopropilacetileno?​
Paladinen [302]
Noooooooooooooooooooooo
3 0
3 years ago
Given the following chemical reaction:
True [87]

Answer:

1

Explanation:

one volume of nitrogen to react

5 0
2 years ago
Rusting of iron is a very common chemical reaction. It results in one form from Fe reacting with oxygen gas to produce iron (III
Vlada [557]

<u>Answer:</u> The given amount of iron reacts with 9.0 moles of O_2 and produce 6.0 moles of Fe_2O_3

<u>Explanation:</u>

We are given:

Moles of iron = 12.0 moles

The chemical equation for the rusting of iron follows:

4Fe+3O_2\rightarrow 2Fe_2O_3

  • <u>For oxygen gas:</u>

By Stoichiometry of the reaction:

4 moles of iron reacts with 3 moles of oxygen gas

So, 12.0 moles of iron will react with = \frac{3}{4}\times 12.0=9.0mol of oxygen gas

  • <u>For iron (III) oxide:</u>

By Stoichiometry of the reaction:

4 moles of iron produces 2 moles of iron (III) oxide

So, 12.0 moles of iron will produce = \frac{2}{4}\times 12.0=6.0mol of iron (III) oxide

Hence, the given amount of iron reacts with 9.0 moles of O_2 and produce 6.0 moles of Fe_2O_3

5 0
3 years ago
If the equilibrium concentrations of products are much greater than those of reactants in this system, what would be the magnitu
miss Akunina [59]

Answer:

K > 1.

Explanation:

∵ The equilibrium constant K = [products]/[reactants].

Since, [products] > [reactants].

<em>∴ The equilibrium constant K > 1.</em>

5 0
3 years ago
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