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worty [1.4K]
2 years ago
6

Using the solubility curves, approximately how many grams of NaNO3 can be dissolved in 100. grams of water at 80 °C?

Chemistry
2 answers:
cestrela7 [59]2 years ago
5 0

Answer:

Answer is B

Explanation:

postnew [5]2 years ago
5 0

Answer:

As temperature increases, its solubility increases as well. Notice, however, that it does not increase significantly. In fact, you can expect to be able to dissolve no more than 40 g of sodium chloride per 100 g of water at 80∘C .

You can determine how many grams of sodium chloride, commonly known as table salt, can be dissolved in

100 g

of water at

80

∘

C

by taking a look at its solubility graph.

A substance's solubility graph tells you how its solubility changes, let's say starting from room temperature, when temperature is either decreased or increased.

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juin [17]

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Boiling- 212° F melting- 32°F

Explanation:

6 0
3 years ago
Match the element with number of valence electrons
Alla [95]

Answer:

Oxygen-O = 6

Carbon C = 4

Gallium G = 3

Astatine A = 7

Arsenic As = 5

Potassium K = 1

Hydrogen H = 1

Helium H = 2

Explanation:

6 0
2 years ago
Can atoms be created or destroyed during a chemical reaction?
ValentinkaMS [17]

Answer:

No.

Explanation:

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7 0
2 years ago
Does anyone know the answer to these?
Rashid [163]

Answer:

The answer to your question is below

Explanation:

Data

mass of CaCO₃ = 155 g

mass of HCl = 250 g

mass of CaCl₂ = 142 g

reactants = CaCO₃ + HCl

products = CaCl₂ + CO₂ + H₂O

1.- Balanced chemical reaction

             CaCO₃ + 2HCl   ⇒    CaCl₂ + CO₂ + H₂O

2.- Limiting reactant

molar mass of CaCO₃ = 40 + 12 + 48 = 100 g

molar mass of HCl = 2[1 + 35.5 ] = 73 g

theoretical proportion CaCO₃ /HCl = 100 / 73 = 1.37

experimental proportion CaCO₃ /HCl = 155 / 250 = 0.62

As the experimental proportion was lower than the theoretical proportion the limiting reactant is CaCO₃

3.-

Calculate the molar mass of CaCl₂

CaCl₂ = 40 + 71 = 111 g

          100 g of CaCO₃ ------------------ 111 g of CaCl₂

           155 g of CaCO₃ ----------------- x

               x = (155 x 111) / 100

               x = 17205 / 100

              x = 172.05 g of CaCl₂

4.- percent yield

Percent yield = 142 / 172.05 x 100 = 82.5 %

5.- Excess reactant

    100 g of CaCO₃  -------------------- 73 g of HCl

     155 g of caCO₃ ------------------- x

           x = (155 x 73)/100

           x = 133.15 g

Mass of HCl = 250 - 133.15

                    = 136.9 g

4 0
2 years ago
Express the following number in scientific notation. 0.53000 = _____
kakasveta [241]
Yes, it would be the last one as the zeros that appear after a non zero number are significant.
7 0
3 years ago
Read 2 more answers
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