All categories

3 years ago

Which is the electron configuration for zinc?

Chemistry

1 answer:

dlinn [17]3 years ago

5 0

Answer:

The electron configuration for zinc is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰. To find electron configuration, simply follow the periodic table from top to bottom, left to right (basically increasing atomic number) until you reach the element you are looking for.

You might be interested in

2. Water is an example of a(n)

Alexus [3.1K]

it would be A ,inorganic Compound

6 0

2 years ago

if three oxygen particles are needed to form ozone, how many units of ozone could be formed from 6 oxygen particles? from 9? fro

tensa zangetsu [6.8K]

<h3>Answers:</h3>

1) 2 Units of Ozone

2) 3 Units of Ozone

3) 9 Units of Ozone

<h3>Solution:</h3>

1) From 6 Oxygen Particles;

As given,

3 Oxygen Particles form = 1 Unit of Ozone

So,

6 Oxygen Particles will form = X Units of Ozone

Solving for X,

X = (6 O Particles × 1 Unit of Ozone) ÷ 3 O Particles

X = 2 Units of Ozone

2) From 9 Oxygen Particles;

As given,

3 Oxygen Particles form = 1 Unit of Ozone

So,

9 Oxygen Particles will form = X Units of Ozone

Solving for X,

X = (9 O Particles × 1 Unit of Ozone) ÷ 3 O Particles

X = 3 Units of Ozone

3) From 27 Oxygen Particles;

As given,

3 Oxygen Particles form = 1 Unit of Ozone

So,

27 Oxygen Particles will form = X Units of Ozone

Solving for X,

X = (27 O Particles × 1 Unit of Ozone) ÷ 3 O Particles

X = 9 Units of Ozone

3 0

3 years ago

All molecular motion stops at 0 on this scale

Oxana [17]

Kelvin Hope this helps

4 0

3 years ago

Read 2 more answers

How many moles of ca(oh)2 are in 25ml of 1.5 M solution?

Klio2033 [76]

Molar concentration is

$C=\frac{\eta}{V}$

$[V]=Liters$

$[\eta]=mol$

$\eta=C*V$

$V=25~mL=0.025~L$

$\eta=1.5*0.025$

$\boxed{\boxed{\eta=0.0375~moles}}$

6 0

3 years ago

at a particulat temperature, a smaple of pure water has a Kw of 7.7x10-14. what is the hydroxide concentration of this sample

ycow [4]

Answer: The hydroxide concentration of this sample is $3.85\times 10^{-7}$

Explanation:

When an expression is formed by taking the product of concentration of ions raised to the power of their stoichiometric coefficients in the solution of a salt is known as ionic product.

The ionic product for water is written as:

$K_w=[H^+]\times [OH^-]$

$7.7\times 10^{-14}=[H^+]\times [OH^-]$

As $[H^+]=[OH^-]$

$2[OH^-]=7.7\times 10^{-14}$

$[OH^-]=3.85\times 10^{-7}$

Thus hydroxide concentration of this sample is $3.85\times 10^{-7}$

4 0

2 years ago