The unit cell volume of the crystal is 
and the density of titanium is calculated as 4.71g/cm^3 while the literature value is 4.5 g/cm^3
Data;
- radius = 0.1445 nm
- c/a = 1.58
- A = 46.88 g/mol
<h3>Unit Cell Volume</h3>
The unit cell volume can be calculated as
let's substitute the values into the formula
The unit cell volume of the crystal is
<h3>Density of Ti</h3>
The density of titanium can be calculated as
- n = 6 for hcp
- A = 46.88 g/mol
- Na = Avogadro's number
let's substitute the values into the formula
The density of titanium is calculated as 4.71g/cm^3 while the literature value is 4.5 g/cm^3
Learn more on crystal lattice here;
brainly.com/question/6610542
The shape, the cell wall, chlorophyll, the components of the nucleus, cytoplasm
Answer:
P(N) = 38.48 mmHg
Explanation:
Given data:
Partial pressure of He = 15.22 mmHg
Partial pressure of O = 35.21 mmHg
Partial pressure of N = ?
Total pressure = 88.91 mmHg
Solution:
According to Dalton law of partial pressure,
The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.
Mathematical expression:
P(total) = P₁ + P₂ + P₃+ ............+Pₙ
Now we will solve this problem by using this law.
P(total) = P(He) + P(O) + P(N)
88.91 mmHg = 15.22 mmHg + 35.21 mmHg + P(N)
88.91 mmHg = 50.43 mmHg + P(N)
P(N) = 88.91 mmHg - 50.43 mmHg
P(N) = 38.48 mmHg
0,35 kmol/m³ = 0,35 mol/dm³ = 0,35 mol/L
175 mL = 0,175 L
*-*-*-*-*-*-*-*-*-*-*-*
C = n/V
n = 0,35×0,175
n = 0,06125 mol
mCa(NO₃)₂: 40+(14×2)+(16×6) = 164 g/mol
1 mol --------- 164g
0,06125 ---- X
X = 10,045g
To prepare 175 mL of 0,35M solution, add 10,045g of calcium nitrate and add water to a volume of 175ml.
