Answer:
The mass chloride is 2.903 grams
Explanation:
Step1: calculate the moles of FeCl3
moles = molarity x volume in liters
volume in liters = 100 ml /1000 = 0.1 L
molarity = 0.273 M = 0.273 mol / L
moles = 0.273 mol /L x 0.1 L = 0.0273 moles
step 2: find the moles of Cl
since there is 3 atoms of cl in FeCl3
= 3 x 0.0273 =0.0819 moles
Step 3: calculate mass of cl
mass= moles x molar mass
=0.0819 moles x 35.45 g/mol = 2.903 g
Answer:
The number of people in that specific area.
Explanation:
Answer:
S = 7.9 × 10⁻⁵ M
S' = 2.6 × 10⁻⁷ M
Explanation:
To calculate the solubility of CuBr in pure water (S) we will use an ICE Chart. We identify 3 stages (Initial-Change-Equilibrium) and complete each row with the concentration or change in concentration. Let's consider the solution of CuBr.
CuBr(s) ⇄ Cu⁺(aq) + Br⁻(aq)
I 0 0
C +S +S
E S S
The solubility product (Ksp) is:
Ksp = 6.27 × 10⁻⁹ = [Cu⁺].[Br⁻] = S²
S = 7.9 × 10⁻⁵ M
<u>Solubility in 0.0120 M CoBr₂ (S')</u>
First, we will consider the ionization of CoBr₂, a strong electrolyte.
CoBr₂(aq) → Co²⁺(aq) + 2 Br⁻(aq)
1 mole of CoBr₂ produces 2 moles of Br⁻. Then, the concentration of Br⁻ will be 2 × 0.0120 M = 0.0240 M.
Then,
CuBr(s) ⇄ Cu⁺(aq) + Br⁻(aq)
I 0 0.0240
C +S' +S'
E S' 0.0240 + S'
Ksp = 6.27 × 10⁻⁹ = [Cu⁺].[Br⁻] = S' . (0.0240 + S')
In the term (0.0240 + S'), S' is very small so we can neglect it to simplify the calculations.
S' = 2.6 × 10⁻⁷ M
<span>pH will be less than 7 at the equivalence point</span>
