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adell [148]
3 years ago
11

When iron sulfide (FeS) is combined with hydrogen chloride (HCl), a gas is formed in a double-displacement reaction. Which gas w

ould it be? A. FeS, B. FeH, C. H2S, D. H2Fe
Chemistry
2 answers:
irakobra [83]3 years ago
3 0
The answer is C. H2s
zhenek [66]3 years ago
3 0

Answer : The correct option is, (C) H_2S gas

Explanation :

Double replacement reaction : It is a type of chemical reaction in which a positive cation and a negative anion of two reactants exchange their places to form two new products.

It is represented as,

XY+AB\rightarrow XB+AY

(X and A are the cations, Y and B are the anions)

When the iron sulfide (FeS) combined with hydrogen chloride (HCl) to give iron(II)chloride and hydrogen sulfide gas as a product.

The balanced chemical reaction will be,

FeS(s)+HCl(l)\rightarrow FeCl_2(s)+H_2S(g)

Hence, the gas would be, (C) H_2S gas

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4 years ago
Is the answer B? Help
Masja [62]

Answer:

A

Explanation:

Hmm, so we have the following in the diagram

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Anode definition: the positively charged electrode by which the electrons leave an electrical device.

Electrode definition: a conductor through which electricity enters or leaves an object, substance, or region.

Cations attracted to cathode pick up electrons

Anions attracted to anode release electrodes+

Reduction at Cathode (red cat gain of e)

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So from the diagram we can see that the charge is being generated through the 2 metal plates.

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7 0
3 years ago
How many moles are in 175g<br> (Ca(NO3)2
zheka24 [161]

Answer:

appx. 1.07 moles

Explanation:

175g of molecule Ca(NO3)2

To find the # of moles, use stoichoimetry.

1. We need the molar mass of Ca(NO3)2.

Ca mass: 40.08 g

NO3 mass: N + 3(O) --> 14.01 + 3(16.00) --> 62.01

Molar mass = Ca + 2(NO3) --> 40.08 + 2(62.01) --> 164.1 g

2. write out the calculation

175g Ca(NO3)2 * (1 mole Ca(NO3)2)/(molar mass of Ca(NO3)2)

175 g Ca(NO3)2 * (1 mole Ca(NO3)2)/(164.1 g Ca(NO3)2)

The g units cancel out and we're left with moles.

Simply perform the calculation now: 175*1/164.1 ≅1.07 moles

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