It is a good thing that you already have answered the first question. Now, moving on to the second question, there exist an equation for the neutralization of acid by a base that is shown below, M₁V₁ = M₂V₂ Now, all the variables in the equation are given except for our unknown which is the V₂. Substituting the known values from the given above, (0.1 M)(25 mL) = (0.05 M)(V₂) The value of V₂ from the equation above is 50 mL. Therefore, 50 mL of 0.05 M NaOH solution will be needed to completely react with HNO3.
