M/6n ÷ 7m/3n PLEASE HELP!

The length of a rectangle is 4 more than the width. Find the width of the rectangle if the area is 32.

Serggg [28]

Answer:

length = 8

width = 4

Step-by-step explanation:

Area = length x breadth

Let x represent the width

length = x + 4

32 = x × (x + 4)

32 = x² + 4x

x² + 4x - 32 = 0

solving using quadratic equation =

(x² - 4x) -32 + 8x

x = 4 or -8

since width cannot be a negative number, we would use 4

7 0

3 years ago

Help!!(thank you so much)

mylen [45]

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

Or just subtract

9.884 * 10^6 - 1.009 * 10^7=

− 2.05999999 × 10^5

Rounded up is:

− 2.06× 10^5

(❁´◡`❁)

8 0

3 years ago

Solve for g.<br><br> –19g = –20g + 12<br><br> g =

Vera_Pavlovna [14]

Answer:

g = 12

Step-by-step explanation:

–19g = –20g + 12

Add 20 g to each side

–19g+20 g = –20g+ 20g + 12

g = 12

4 0

3 years ago

Read 2 more answers

What is the area,in the square units,of the rectangle?

deff fn [24]

Step-by-step explanation:

$area = l \times b$

$area = \frac{3}{7} \times \frac{2}{9}$

$area = \frac{6}{64}$

$area = 0.09375units ^{2}$

7 0

2 years ago

Consider the probability that at least 88 out of 158 software users will not call technical support. Assume the probability that

Nookie1986 [14]

Answer:

$E(X) = 158*0.57 =90.06$

And the standard deviation for the random variable is given by:

$\sigma= \sqrt{158*0.57*(1-0.57)} = 6.223$

And the distribution for the approximation is given by:

$X \sim N (\mu = 90.06, \sigma = 6.223)$

We can use the z score formula given by:

$z = \frac{x -\mu}{\sigma}$

And using the complement rule we got:

$P(X \geq 88) = 1-P(X$

And using the standard normal table we got:

$P(X \geq 88) = 1-P(X$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Bin (n = 158, p =0.57)$