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Dimas [21]
3 years ago
14

Hey can you please help me posted picture of question

Mathematics
1 answer:
Anika [276]3 years ago
4 0
When a number is added to or subtracted from a function it moves it vertically up or down.

G(x) is obtained by subtracting 3 from F(x). This means G(x) is obtained by vertical translation of F(x). Since 3 is subtracted from F(x), the vertical translation is downwards.

So, we can say: G(x) is obtained by moving F(x) 3 units vertically down.

Therefore, the correct answer is option D
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The point (Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, StartFraction StartRoot 2 EndRoot Over 2 EndFraction)
sveticcg [70]

The values of cosine Ф and cotangent Ф are \frac{-\sqrt{2} }{2} and -1

Step-by-step explanation:

When a terminal side of an angle intersect the unit circle at

point (x , y), then:

  • The x-coordinate is equal to cosine the angle between the positive part of x-axis and the terminal side
  • The y-coordinate is equal to sine the angle between the positive part of x-axis and the terminal side
  • If x and y coordinates are positive, then the angle lies in the 1st quadrant
  • If x-coordinate is negative and y-coordinate is positive, then the angle lies in the 2nd quadrant
  • If x and y coordinates are negative, then the angle lies in the 3rd quadrant
  • If x-coordinate is positive and y-coordinate is negative, then the angle lies in the 4th quadrant

∵ The terminal ray of angle Ф intersects the unit circle at point (\frac{-\sqrt{2} }{2},\frac{\sqrt{2} }{2})

- According to the 1st and 2nd notes above

∴ cosФ = x-coordinate of the point

∴ sinФ = y-coordinate of the point

∵ The x-coordinate of the point is negative

∵ They-coordinate of the point is positive

- According the the 4th note above

∴ Angle Ф lies in the 2nd quadrant

∵ x-coordinate = \frac{-\sqrt{2} }{2}

∴ cosФ = \frac{-\sqrt{2} }{2}

∵ y-coordinate = \frac{\sqrt{2} }{2}

∴ sinФ = \frac{\sqrt{2} }{2}

- cotФ is the reciprocal of tanФ

∵ tanФ = sinФ ÷ cosФ

∴ cotФ = cosФ ÷ sinФ

∴ cotФ = \frac{-\sqrt{2} }{2} ÷ \frac{\sqrt{2} }{2}

∴ cotФ = -1

The values of cosine Ф and cotangent Ф are \frac{-\sqrt{2} }{2} and -1

Learn more:

You can learn more about the trigonometry function in brainly.com/question/4924817

#LearnwithBrainly

4 0
3 years ago
Read 2 more answers
Can someone explain to me how to do question number 6 please?
slavikrds [6]
Hope this helps but try to do process of elimination.
7 0
3 years ago
What is the value of B ?
Virty [35]

Answer: 70.1

Step-by-step explanation:

8 0
3 years ago
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Make sure to use complete sentences in your answer 1.6084*10^3
Nikolay [14]
1.6084 * 10^3 simplifies to 1608.4
6 0
4 years ago
3.2g of sugar is needed to make 8 cakes. How much sugar is needed for 12 cakes?
4vir4ik [10]

3.2s:8c

4.8s:12c

Therefore, you would need 4.8g of sugar to make 12 cakes. This was solved by using ratios.

8 0
3 years ago
Read 2 more answers
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