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Gelneren [198K]
3 years ago
7

10. Isolation of a pure sample of the third product, which has been determined to be an isomer of the major and minor products,

gives the following 13C NMR data. Determine the structure of this product. 2 points

Chemistry
1 answer:
Ymorist [56]3 years ago
7 0

Answer:

Four possible isomers (1–4) for the natural product essramycin. The structure of compound 1 was attributed to essramycin by 1H NMR, 13C NMR, HMBC, HRMS, and IR experiments.

Explanation:

Three synthetic routes were used to prepare all four compounds (Figure 2A). All three reactions utilize 2-(5-amino-4H-1,2,4-triazol-3-yl)-1-phenylethanone (5) as the precursor, whereas each uses different esters (6–8) to construct the pyrimidinone ring. Isomer 1 was prepared by reaction A, which used triazole 5 and ethyl acetoacetate (6) in acetic acid. This was the reaction used in syntheses of essramycin by the Cooper and Moody laboratories.3,4 Reaction B produced compound 2 (minor product) and compound 3 (major product), which were separated chromatographically. This reaction allowed reagent 5 to react with ethyl 3-ethoxy-2-butenoate (7) in the presence of sodium in methanol, under reflux for 24 h. Compound 4 was prepared by reaction C, which was obtained by reflux of 5 and methyl 2-butynoate (8) in n-butanol.

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The absorbance of a cationic iron(II) sample solution was measured in a spectrophotometer, but the instrument returned an error
JulijaS [17]

Answer:

1.35\times 10^{-4} M was the concentration of the original solution.

Explanation:

M_1V_1=M_2V_2  (Dilution)

where,

M_1\text{ and }V_1 are molarity and volume of non diluted sample.

M_2\text{ and }V_2 are molarity and volume of diluted sample.

M_1=?

V_1=100.0 \mu L=0.1 mL

(1μL=0.001  mL)

M_2=6.41\times 10^{-6} M

V_2=2.00 mL + 100.0 \mu L=2.00 mL+0.1 mL=2.1 mL

Substituting all values :

M_1\times 0.1 mL=6.41\times 10^{-6} M\times 2.1 mL

M_1=\frac{6.41\times 10^{-6} M\times 2.1 mL}{0.1 mL}=1.35\times 10^{-4} M

1.35\times 10^{-4} M was the concentration of the original solution.

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3 years ago
Please help asap.....
vampirchik [111]
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The answer is B, Urbanisation.

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r3t40
3 0
3 years ago
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Need help ASAP!!!! what is the value (angle) for the C=C=O bond in Ketene i.e. CH2=C=O
stepan [7]

Answer:

180^\circ by the VSEPR theory.

Explanation:

This question is asking for the bond angle of the \rm C=C=O bond in \rm H_2C=C=O. The VSEPR (valence shell electron pair repulsion) theory could help. Start by considering: how many electron domains are there on the carbon atom between these two bond?

Note that "electron domains" refer to covalent bonds and lone pairs collectively.

  • Each nonbonding pair (lone pair) of valence electrons counts as one electron domain.
  • Each covalent bond (single bond, double bond, or triple bond) counts as exactly one electron domain.

For example, in \rm H_2C=C=O, the carbon atom at the center of that \rm C=C=O bond has two electron domains:

  • This carbon atom has two double bonds: one \rm C=C bond and one \rm C=O bond. Even though these are both double bonds, in VSEPR theory, each of them count only as one electron domain.
  • Keep in mind that there are only four valence electrons in each carbon atom. It can be shown that all four valence electrons of this carbon atom are involved in bonding (two in each of the two double bonds.) Hence, there would be no nonbonding pair around this atom.

In VSEPR theory, electron domains around an atom repel each other. As a result, they would spread out (in three dimensions) as far away from each other as possible. When there are only two electron domains around an atom, the two electron domains would form a straight line- with one domain on each side of the central atom. (To visualize, consider the three atoms in this \rm C=C=O bond as three spheres on a stick. The central \rm C atom would be between the other \rm C atom and the \rm O atom.)

This linear geometry corresponds to a bond angle of 180^\circ.

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A surface wave is a combination of what two waves
Alika [10]

transverse wave and a longitudinal wave

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4 0
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Solid NaCl is produced by the
soldi70 [24.7K]

Answer:

2Na (s) +  Cl2 (g) -->2NaCl (s) + heat

Explanation:

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