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Jlenok [28]
2 years ago
13

Does food passes through liver, pancreas and appendix?

Chemistry
2 answers:
Bond [772]2 years ago
8 0
Yes its does pass ............!!!!!!!!!!!
Ksivusya [100]2 years ago
6 0

Answer: yes

Explanation:

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The pressure in car tires is often measured in pounds per square inch (lb/in.2), with the recommended pressure being in the rang
Minchanka [31]

Answer:

2.62 atm

Explanation:

1 atm = 14.6959 psi

38.5 / 14.6959 = 2.62 atm

4 0
1 year ago
Aspirin tablets contain the active ingredient (aspirin) and various inactive ingredients. Suggest what types of inactive ingredi
Debora [2.8K]
Binders ; fillers. They are inert substances to hold pill shape and preserve the medication, its ph / etc.

5 0
3 years ago
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 4.90 moles of magnesium perchlorate, Mg(ClO4)2.]\
Leviafan [203]

Answer:

 4.90  moles of  Mg(ClO_4)_2   will produce  (9.8) moles of  Cl^{-} ,

                                                    (4.90) moles of Mg^{2+} and

                                                    (39.2) moles of  O^{2-}

Explanation:

From the question we are told that

  The number of moles of  is  n =  4.90  \ mols

The formation reaction of Mg(ClO_4)_2  is

             Mg^{2+} + 2 Cl^{-} + 8O^{2+} \to Mg(ClO_4)_2  

From the reaction we see that

   1 mole of  Mg(ClO_4)_2  is formed by 2 moles of Cl^{-} 1 mole of  Mg^{2+} and 4  O^{2-}

 This implies that

   4.90  moles of  Mg(ClO_4)_2   will produce  (2 * 4.90) moles of  Cl^{-} ,

                                                    (1 * 4.90) moles of Mg^{2+} and

                                                    (8 * 4.90) moles of  O^{2-}

So

  4.90  moles of  Mg(ClO_4)_2   will produce  (9.8) moles of  Cl^{-} ,

                                                    (4.90) moles of Mg^{2+} and

                                                    (39.2) moles of  O^{2-}

                           

4 0
2 years ago
Read 2 more answers
Does anybody know how to do q4. Please show working out thanks.
insens350 [35]

Answer:

% purity of limestone = 96.53%

Explanation:

Question (4).

Weight of impure CaCO₃ = 25.9 g

Molecular weight of CaCO₃ = 40 + 12 + 3(16)

                                              = 100 g per mole

We know at S.T.P. number of moles of CO₂ = 1 and volume = 22.4 liters

From the given reaction, 1 mole of CaCO₃ reacts with 1 mole or 22.4 liters of

CO₂.

∵ 22.4 liters of CO₂ was produced from CaCO3 = 100 g

∴ 1 liter of CO₂ will be produced by CaCO₃ = \frac{100}{22.4}

∴ 5.6 liters of CO₂ will be produced by CaCO₃ = \frac{100\times 5.6}{22.4}

                                                                              = 25 g

Therefore, % purity of CaCO₃ = \frac{\text{Weight calculated}}{{\text{Weight given}}}\times 100

                                                 = \frac{25}{25.9}\times 100

                                                 = 96.53 %

7 0
3 years ago
If the solvent front is 68 mm and the ring front of an unknown is 48mm from the original spot, what is the rf value?
Nat2105 [25]

<u>Given:</u>

Distance of solvent front = 68 mm

Distance of unknown = 48 mm

<u>To determine:</u>

The rf value

<u>Explanation:</u>

The retention factor or the rf value is given by the ratio of distance traveled by the unknown to the distance traveled by the solvent front

RF = distance by unknown/distance by solvent

RF = 48/68 = 0.706

Ans: the RF value is 0.706

3 0
3 years ago
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