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3 years ago

Helpppp!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Chemistry

1 answer:

castortr0y [4]3 years ago

6 0

Answer:

mk, ill try. also im listing them left to right

Explanation:

first row: carbon, oxygen, chlorine, nitrogen

second row: chlorine, glucose, sodium chloride, cobalt

third: hydrogen chloride (i dont know the others and dont want to get them wrong but hope this helped in some sort of way)

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Can you guys help me fill out the table?

TEA [102]

Explanation:

Scientist Evidence Model

Dalton Gases indivisible, solid and spheres

J.J Thomson Deflected beam Negative charges evenly scattered

through positively charged mass of

matter.

Rutherford Deflection of alpha atomic model

particles passing

through the gold foil

The emboldened words are the answer.

John Dalton proposed the first model of the atoms by his works on gases. He postulated the Dalton's law of partial pressure.
He suggested that gases are made of tiny particles called atoms.

J.J Thomson proposed the plum pudding model of the atom in which the charges are evenly scattered through the positively charged mass of matter.

The gold foil experiment by Rutherford brought the atomic model of the atoms in the front-light.
The model suggests a small positively charged center which the mass of the atom.
The outer space is occupied by the electrons.

Learn more:

Rutherford brainly.com/question/1859083

#learnwithBrainly

6 0

3 years ago

A pool is 60.0 m long and 35.0 m wide. How many mL of water are needed to fill the pool to an average depth of 6.35 ft? Enter yo

ra1l [238]

Answer:

4.07 × 10⁹ mL

Explanation:

Step 1: Given data

Length of the pool (L): 60.0 m

Width of the pool (W): 35.0 m

Depth of water in the pool (D): 6.35 ft

Step 2: Convert "D" to m

We will use the relationship 1 m = 3.28 ft

$6.35ft \times \frac{1m}{3.28ft} = 1.94m$

Step 3: Calculate the volume of water (V)

We will use the following expression.

$V = L \times W \times D = 60.0m \times 35.0m \times 1.94 m = 4.07 \times 10^{3} m^{3}$

Step 4: Convert "V" to mL

We will use the relationship 1 m³ = 10⁶ mL.

$4.07 \times 10^{3} m^{3} \times \frac{10^{6}mL }{1m^{3} } = 4.07 \times 10^{9} mL$

7 0

3 years ago

Side Show

den301095 [7]

Answer: if you have this app then you’r not smart

Explanation: because cheating is not allowed

4 0

3 years ago

18.A 2.50 L sample of dry air in a cylinder exerts a pressure of

Vlada [557]

Answer:

$\boxed{\text{7.50 L}}$

Explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

$p_{1}V_{1} = p_{2}V_{2}$

Data:

$\begin{array}{rclrcl}p_{1}& =& \text{3.00 atm}\qquad & V_{1} &= & \text{2.50 L} \\p_{2}& =& \text{1.00 atm}\qquad & V_{2} &= & ?\\\end{array}$

Calculations:

$\begin{array}{rcl}3.00 \times 2.50 & =& 1.00V_{2}\\7.500 & = & 1.00V_{2}\\V_{2} & = &\textbf{7.50 L}\\\end{array}\\\text{The volume of the gas is } \boxed{\textbf{7.50 L}}$

4 0

3 years ago

1. A gas has a pressure of 799.0 mm Hg at 50.0 degrees C. What is the temperature at standard Pressure?

larisa [96]

Answer:

A = 674.33mmHg

B = 0.385atm

Explanation:

Both question A and B requires the application of pressure law which states that the pressure of a fixed mass of gas is directly proportional to its temperature provided that volume is kept constant.

Mathematically,

P = kT, k = P / T

P1 / T1 = P2 / T2 = P3 / T3 =.......= Pn/Tn

Data:

P1 = 799mmHg

T1 = 50°C = (50 + 273.15) = 323.15K

P2 = ?

T2 = 273.15K

P1 / T1 = P2 / T2

Solve for P2

P2 = (P1 × T2) / T1

P2 = (799 × 273.15) / 323.15

P2 = 674.37mmHg

The final pressure is 674.37mmHg

P1 = 0.470atm

T1 = 60°C = (60 + 273.15)K = 333.15K

P2 = ?

T2 = 273.15K

P1 / T1 = P2 / T2

Solve for P2,

P2 = (P1 × T2) / T1

P2 = (0.470 × 273.15) / 333.15

P2 = 0.385atm

The final pressure is 0.385atm

7 0

3 years ago

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