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3 years ago

8

El etanol combustiona con el oxigeno produciendo dióxido de carbono gaseoso y agua: En un proceso se hacen reaccionar 450.2 g de

dioxígeno con 998. 2 g de etanol . a) ¿Cuál de los reactivos es el limitante? b) Calcule la masa de dióxido de carbono que se formará c) ¿ Cuanto del reactivo en exceso quedará sin reaccionar?

1 answer:

Olenka [21]3 years ago

6 0

Answer:

uh oh stinky uh oh stinky

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Taya2010 [7]

Answer:

The correct answer is B) electronegativities of the bonded atoms in a molecule of the compound .

Explanation:

When two atoms forming a bond differ in their electronegativities at that time bond polarity is generated

In simple words a bond will be polar when the bonding electrons are not equally shared by two atoms.As a result the atom attract the bonding electron pair towards itself gain partial negative charge and the other atom gains partial positive charge.

For HCl is a polar compound because H and Cl atom differ in their electronegativities,as a result the bonding electron pair is not shared equally by H and Cl atoms.

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3 years ago

What is the name of this compound?

Monica [59]

Answer:

THERE IS NOTHING MENTION HERE HOW CAN ANYONE KNOW ABOUT IT?]

Explanation:

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3 years ago

Hexane and heptane are miscible with each other in all proportions. In making a solution of them, is the entropy of the system i

Damm [24]

Answer: Option (a) is the correct answer.

Explanation:

A miscible solution is defined as the one in which two or more than two components are soluble with each other.

So, when hexane is added to heptane then both of them will mix with each other and hence they are miscible. This mixing will lead to formation of more number of ions into the solution as a result, more will be the disorder present in the solution.

As entropy is the degree of randomness present.

Hence, we can conclude that a solution of hexane and heptane will lead to an increase in entropy.

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4 years ago

Start with 100.00 mL of 0.10 M acetic acid, CH3COOH. The solution has a pH of 2.87 at 25 oC. a) Calculate the Ka of acetic acid

jasenka [17]

Answer: a) The $K_a$ of acetic acid at $25^0C$ is $1.82\times 10^{-5}$

b) The percent dissociation for the solution is $4.27\times 10^{-3}$

Explanation:

$CH_3COOH\rightarrow CH_3COO^-H^+$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.10 M and $\alpha$ = ?

Also $pH=-log[H^+]$

$2.87=-log[H^+]$

$[H^+]=1.35\times 10^{-3}M$

$[CH_3COO^-]=1.35\times 10^{-3}M$

$[CH_3COOH]=(0.10M-1.35\times 10^{-3}=0.09806M$

Putting in the values we get:

$K_a=\frac{(1.35\times 10^{-3})^2}{(0.09806)}$

$K_a=1.82\times 10^{-5}$

b) $\alpha=\sqrt\frac{K_a}{c}$

$\alpha=\sqrt\frac{1.82\times 10^{-5}}{0.10}$

$\alpha=4.27\times 10^{-5}$

$\% \alpha=4.27\times 10^{-5}\times 100=4.27\times 10^{-3}$

5 0

4 years ago

What is the pH of a solution whose H + concentration is 4.0 10 –9?

Dmitrij [34]

Answer:

he pH of a solution is defined as the negative log10 [H+] ... 1 x 10-11. 11. Acidic Solution. 1 x 10-4. 4. 1 x 10-10. 10. 1 x 10-5. 5. 1 x 10-9.

Explanation:

m

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3 years ago