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djyliett [7]
3 years ago
6

How much work (in J) is involved in a chemical reaction if the volume decreases from 5.00 to 1.48 L against a constant pressure

of 0.819 atm?
Chemistry
1 answer:
Dahasolnce [82]3 years ago
5 0
Given:
ΔV = 5 - 1.48 L = 3.52 L = 0.00352 m³, th chane in volume
p = 0.818 atm = 0.819*101325 Pa = 82985.2 Pa

By definition, the work done is
W = \int pdV = (82985.2 \,  \frac{N}{m^{2}} )*(0.00352 \, m^{3}) = 292.1 \, J

Answer: 292.1 J
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Is a nylon string conductor or insulator
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Suppose you carry out a titration involving 3.00 molar HCl and an unknown concentration of KOH. To bring the reaction to its end
snow_tiger [21]

Answer: The concentration of the KOH solution is 1.01 M

Explanation:

According to neutralization law:

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity of HCl = 1

n_2 = acidity of KOH = 1

M_1 = concentration of HCl = 3.00 M

M_2 = concentration of KOH = ?

V_1 = volume of HCl = 35.3 ml

V_2 = volume of KOH = 105.0 ml

Putting the values we get:

1\times 3.00\times 35.3=1\times M_2\times 105.0

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Thus the concentration of the KOH solution is 1.01 M

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4 years ago
Which of the following are strong electrolytes in water?
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Answer:

Ionic compounds that ionize completely in water

8 0
3 years ago
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the balloon is inflated outdoors on a cold day in North Dakota at a temperature of -35°C to a volume of 3.0 L. The pressure rema
iragen [17]

3.75 litres is the volume of the balloon indoors at a temperature of 25°C.

Explanation:

Data given:

initial temperature of the gas in balloon  = -35°C or 238.15 K

initial volume = 3 litres

final temperature = 25 °C  or 298.15 K

final volume =?

pressure remains constant

From the data given when pressure is constant Charles' law is applied.

\frac{V1}{T1} = \frac{V2}{T2}

Rearranging the equation to know the final volume of the gas in balloon

V2 = \frac{V1T2}{T1}

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when the temperature of a gas is increased and pressure remains constant the volume of the gas increases.

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3 years ago
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Answer:

rate = [NO]²[H₂]

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