E. co and n2Effusion is the process where gas escapes through a hole. Gases with a lower molecular mass effuse more speedy than gases with a higher molecular mass. R<span>elative rates of effusion is related to the molecular mass.
a) M(N</span>₂)/M(O₂) = 28/32 = 0,875
b) M(N₂O)/M(NO₂) = 44/46 = 0,956
c) M(CO)/M(CO₂) = 28/44 = 0,636
d) M(NO₂)/M(N₂O₂) = 44/58= 0,758
e) M(CO)/M(N₂) = 28/28 = 1, <span>CO and N</span>₂ <span>have iexact molecular masses and will effuse at nearly identical rates.</span>
Answer:
Both
Explanation:
The combined gas law is also known as the general gas law.
From the ideal gas law we assume that n = 1;
So;
PV = nRT
and then;
= 
If we cross multiply;
P₁V₁T₂ = P₂V₂T₁
So;
T₁ = 
Also;
V₂ = 
So from the choices both are correct
Your answer would be respiration. This would be your answer because, plants take in carbon dioxide, and animals, including humans, breath oxygen. I hope this had helped you out.
Answer:I believe your answer would be option B) dilute. Hope this helps.
Explanation:
When iron rusts and forms iron oxide, the iron oxide has more mass than the iron because there are more iron atoms in iron oxide than in pure iron.
The process of rust occurs when pure iron is exposed to air and moisture. Rust is the oxidation of pure iron to iron II oxide (Fe2O3).
We can see that there are two iron atoms per mole of Fe2O3 whereas there is only one iron atom in each mole of pure iron.
Therefore, iron oxide has more mass than the iron because there are more iron atoms in iron oxide than in pure iron.
Learn more; brainly.com/question/18376414
