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erik [133]
3 years ago
12

An electromagnetic wave traveling through space encounters an electron sitting at rest. Upon being hit by the wave, which way wi

ll the electron move?
A. It will bob up and down with the crests and troughs
B. It'll be pushed entirely along the direction the wave is moving (perpendicular to the crests and troughs)
C. It won't move at all
D. It'll both bob up and down and be pushed along the direction the wave is moving
Physics
1 answer:
Romashka [77]3 years ago
7 0

Answer:

D) True. Explain the oscillation and movement in the direction of the wave

Explanation:

To review the possible answers, let's look at the characteristics of the electromagnetic wave.

The wave has a fluctuating electric field and magnetic field, perpendicular to its direction of movement, these fields interact with the electron by measuring the electric force

The speed of the wave is perpendicular to the fluctuating fields (transverse wave). This wave exerts a radiation pressure on the particles that it finds, in its path, since it carries energy, this pressure is a force that pushes the direction electron The wave is traveling.

Let's check the answers

A) False. The electron will oscillate with the frequency of the wave, but the movement does not explain the direction of the wave

B) False. It is pushed by the radiation pressure, but does not explain the oscillation of the electron

C) False. Does it move

D) True. Explain the oscillation and movement in the direction of the wave

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A train travels due south at 25 m/s (relative to the ground) in a rain that is blown toward the south by the wind. The path of e
olasank [31]

Answer:

Explanation:

Given

Train travels towards south with a velocity if v_t=25\ m/s

Rain makes an angle of \theta =66^{o}  with vertical

If an observer sees the drop fall perfectly vertical i.e. horizontal component of rain velocity is equal to train velocity

suppose v_r is the velocity of rain with respect to ground then

v_r\sin\theta =v_t

v_r\times \sin (66)=25

v_r=27.36\ m/s

Therefore velocity of rain drops is 27.36 m/s              

8 0
3 years ago
a street light is mounted at the top of a 15 foot pole. A man 6 ft tall walks away from the pole wit a speed of 7 ft/s along a s
Mariulka [41]

Answer:

16.3 ft/s

Explanation:

Let d=distance

and

x = length of shadow.

Therfore,

x=(d + x)

 = 6/15

So,

    15x = 6x + 6d

     9x = 6d.

x = (2/3)d.

As we know that:

dx=dt

   = (2/3) (d/dt) 

Also,

Given:

d(d)=dt

     = 7 ft/s

Thus,

d(d + x)=dt

           = (7/3)d (d/dt)

Substitute, d= 7  

d(d + x) = 49/3 ft/s.

Hence,

d(d + x) = 16.3 ft/s.

4 0
3 years ago
Put the waves in order from highest frequency to lowest frequency
S_A_V [24]
BCA for sure, b the lines are showing more movement
6 0
3 years ago
Read 2 more answers
Violet light of wavelength 405 nm ejects electrons with a maximum kinetic energy of 0.890 eV from a certain metal. What is the b
AleksandrR [38]

Answer:

  Ф = 2.179 eV

Explanation:

This exercise has electrons ejected from a metal, which is why it is an exercise on the photoelectric effect, which is explained assuming the existence of energy quanta called photons that behave like particles.

            E = K + Ф

the energy of the photons is given by the Planck relation

            E = h f

we substitute

           h f = K + Ф

           Ф= hf - K

the speed of light is related to wavelength and frequency

            c = λ f

            f = c /λ

            Φ = \frac{hc}{\lambda } - K

let's reduce the energy to the SI system

            K = 0.890 eV (1.6 10⁻¹⁹ J / 1eV) = 1.424 10⁻¹⁹ J

calculate

           Ф = 6.63 10⁻³⁴ 3 10⁸/405 10⁻⁹  -1.424 10⁻¹⁹

           Ф = 4.911 10⁻¹⁹ - 1.424 10⁻¹⁹

           Ф = 3.4571 10⁻¹⁹ J

         

we reduce to eV

           Ф = 3.4871 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

           Ф = 2.179 eV

4 0
2 years ago
Khaled said the North star is special because it appears all over the world and its changes position.
saw5 [17]
False the North Star never changes it position
3 0
2 years ago
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