1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
erik [133]
3 years ago
12

An electromagnetic wave traveling through space encounters an electron sitting at rest. Upon being hit by the wave, which way wi

ll the electron move?
A. It will bob up and down with the crests and troughs
B. It'll be pushed entirely along the direction the wave is moving (perpendicular to the crests and troughs)
C. It won't move at all
D. It'll both bob up and down and be pushed along the direction the wave is moving
Physics
1 answer:
Romashka [77]3 years ago
7 0

Answer:

D) True. Explain the oscillation and movement in the direction of the wave

Explanation:

To review the possible answers, let's look at the characteristics of the electromagnetic wave.

The wave has a fluctuating electric field and magnetic field, perpendicular to its direction of movement, these fields interact with the electron by measuring the electric force

The speed of the wave is perpendicular to the fluctuating fields (transverse wave). This wave exerts a radiation pressure on the particles that it finds, in its path, since it carries energy, this pressure is a force that pushes the direction electron The wave is traveling.

Let's check the answers

A) False. The electron will oscillate with the frequency of the wave, but the movement does not explain the direction of the wave

B) False. It is pushed by the radiation pressure, but does not explain the oscillation of the electron

C) False. Does it move

D) True. Explain the oscillation and movement in the direction of the wave

You might be interested in
What is the speed of light ?​
Brrunno [24]

Answer:

299792458 metres per second

Explanation:

3 0
3 years ago
Two velcro-covered pucks slide across the ice, collide and stick to one another. Their interaction with the ice is frictionless.
balu736 [363]

Answer:

<em>1. False</em>

<em>2. True</em>

<em>3. False</em>

<em>4. True</em>

Explanation:

<u>Conservation of Momentum</u>

According to the law of conservation of linear momentum, the total momentum of the system formed by both pucks won't change regardless of their interaction if no external forces are acting on the system.

The momentum of an object of mass ma moving at speed va is

p_a=m_a.v_a

The total momentum of both pucks at the initial condition is

p_1=m_a.v_a+m_b.v_b

Both pucks are moving to the right and puck B has twice the mass of puck A (let's call it m), thus

m_a=m

m_b=2m

We are given

v_a=6\ m/s\\v_b=2\ m/s

The total initial momentum is

p_1=6m+2(2m)=10m

At the final condition, both pucks stick together, thus the total mass is 3m and the final speed is common, thus

p_2=3m.v'

Equating the initial and final momentum

10m=3m.v'

Solving for v'

v'=10/3\ m/s=3.33\ m/s

1. Compute the initial kinetic energy:

\displaystyle K_1=\frac{1}{2}mv_a^2+\frac{1}{2}2mv_b^2

\displaystyle K_1=\frac{1}{2}m\cdot 6^2+\frac{1}{2}2m\cdot 2^2

K_1=18m+4m=22m

The final kinetic energy is

\displaystyle K_2=\frac{1}{2}mv'^2+\frac{1}{2}2mv'^2

\displaystyle K_2=\frac{1}{2}m\cdot 3.33^2+\frac{1}{2}2m\cdot 3.33^2

K_2=16.63m

As seen, part of the kinetic energy is lost in the collision, thus the statement is False

2. The initial speed of puck B was 2 m/s and the final speed was 3.33 m/s, thus it increased the speed: True

3. The initial speed of puck A was 6 m/s and the final speed was 3.33 m/s, thus it decreased the speed: False

4. The momentum is conserved since that was the initial assumption to make all the calculations. True

p_1=10m

p_2=3m.v'=3m(10/3)=10m

Proven

5 0
3 years ago
HELP ME ILL MARK YOU THE BRAINLIEST
OleMash [197]

Option C: Later in the day, less power is developed in lifting each box

7 0
3 years ago
Read 2 more answers
A ball with a mass of 170 g which contains 3.80×108 excess electrons is dropped into a vertical shaft with a height of 145 m . A
yaroslaw [1]

Answer:

A. F=6.65*10^{-10}N

B. south - north

Explanation:

A) We use the Lorentz force

F = qv X B

|F| = qvB

to calculate the magnitude of the force we need the speed of the of the ball.

v_{f}^{2}=v_{0}^{2}+2gy\\v_{f}=\sqrt{0+2(9.8\frac{m}{s^{2}})(145m)}=53.31\frac{m}{s}

and by replacing in the formula for the magnitude of the force we have (taking into account the excess of electrons)

F=(3.8*10^{8})(1.602*10^{-19}C)(53.31\frac{m}{s})(0.205T)=6.65*10^{-10}N

B)

b.  south - north (by the rigth hand rule)

I hope this is usefull for you

regards

8 0
3 years ago
What is the final velocity of a body if it is moving with 13 m/s in 300 seconds and its acceleration is 30 m/s 2.
Nutka1998 [239]

Answer:

9013m/s

Explanation:

acceleration= v- u/ t

=> at = v-u

=> v = at + u

=> v =30*300+13

= 9013m/s

6 0
3 years ago
Other questions:
  • A 60 tooth gear is connected to a 72 tooth gear
    12·2 answers
  • The chief by 3 3/4 kg of Apple's 7 1/4 kilograms of peers and 10 1/8 kilograms with orange about how many kilograms of fruit did
    7·2 answers
  • Consider resistors R1 and R2 connected in series E R1 R2 and in parallel E R1 R2 to a source of emf E that has no internal resis
    6·1 answer
  • Two 1.0 kg masses are 1.0 m apart (center to center) on a frictionless table. Each has a +10μC of charge. a) What is the magnitu
    15·1 answer
  • 1. In a Millikan type experiment, two horizontal plates are 2.5 cm apart. A latex sphere of
    11·1 answer
  • Multiply 2 cm by 100 to convert to meters​
    13·1 answer
  • Someone pls help mee
    10·1 answer
  • Why do you sometimes get shocked by static electricity? Explain how it happens and give an example.
    15·1 answer
  • A building is 6m high, and it is 80m from a converging camera lens. If the camera forms an image which is 6 mm high, (a) What is
    14·1 answer
  • A jet flew from Kennedy Airport in New York City to Orlando, Florida, in
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!