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erik [133]
3 years ago
12

An electromagnetic wave traveling through space encounters an electron sitting at rest. Upon being hit by the wave, which way wi

ll the electron move?
A. It will bob up and down with the crests and troughs
B. It'll be pushed entirely along the direction the wave is moving (perpendicular to the crests and troughs)
C. It won't move at all
D. It'll both bob up and down and be pushed along the direction the wave is moving
Physics
1 answer:
Romashka [77]3 years ago
7 0

Answer:

D) True. Explain the oscillation and movement in the direction of the wave

Explanation:

To review the possible answers, let's look at the characteristics of the electromagnetic wave.

The wave has a fluctuating electric field and magnetic field, perpendicular to its direction of movement, these fields interact with the electron by measuring the electric force

The speed of the wave is perpendicular to the fluctuating fields (transverse wave). This wave exerts a radiation pressure on the particles that it finds, in its path, since it carries energy, this pressure is a force that pushes the direction electron The wave is traveling.

Let's check the answers

A) False. The electron will oscillate with the frequency of the wave, but the movement does not explain the direction of the wave

B) False. It is pushed by the radiation pressure, but does not explain the oscillation of the electron

C) False. Does it move

D) True. Explain the oscillation and movement in the direction of the wave

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aleksandr82 [10.1K]

Answer:

A(t) = -340e^{-t/70} + 350

Explanation:

Since fluid is pumping in and out at the same rate (5L/min), the total fluid volume in the tank stays constant at 350L. Only the amount of salt and its concentration changed overtime.

Let A(t) be the amount of salt (g) at time t and C(t) (g/L) be the concentration at time t

A(0) = 10 g

Brine with concentration of 1g/L is pouring in at the rate of 5L/min so the salt income rate is 5 g/min

The well-mixed solution is pouring out at the rate of 5L/min at concentration C(t) so the salt outcome rate is 5C g/min

But the concentration is total amount of salt over 350L constant volume

C = A / 350

Therefore our rate of change for salt A' is

A' = 5 - 5A/350 = 5 - A/70

This is a first-order linear ordinary differential equation and it has the form of y' = a + by. The solution of this is

y = ce^{bt} + \frac{a}{b}

So A = ce^{\frac{-t}{70}} + \frac{5}{1/70} = ce^{-t/70} + 350

with A(0) = 10

c + 350 = 10

c = 10 - 350 = -340

A(t) = -340e^{-t/70} + 350

4 0
3 years ago
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alexgriva [62]

Answer: A, B, and D,

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6 0
2 years ago
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ikadub [295]

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Explanation:

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Answer:

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Explanation:

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