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erik [133]
3 years ago
12

An electromagnetic wave traveling through space encounters an electron sitting at rest. Upon being hit by the wave, which way wi

ll the electron move?
A. It will bob up and down with the crests and troughs
B. It'll be pushed entirely along the direction the wave is moving (perpendicular to the crests and troughs)
C. It won't move at all
D. It'll both bob up and down and be pushed along the direction the wave is moving
Physics
1 answer:
Romashka [77]3 years ago
7 0

Answer:

D) True. Explain the oscillation and movement in the direction of the wave

Explanation:

To review the possible answers, let's look at the characteristics of the electromagnetic wave.

The wave has a fluctuating electric field and magnetic field, perpendicular to its direction of movement, these fields interact with the electron by measuring the electric force

The speed of the wave is perpendicular to the fluctuating fields (transverse wave). This wave exerts a radiation pressure on the particles that it finds, in its path, since it carries energy, this pressure is a force that pushes the direction electron The wave is traveling.

Let's check the answers

A) False. The electron will oscillate with the frequency of the wave, but the movement does not explain the direction of the wave

B) False. It is pushed by the radiation pressure, but does not explain the oscillation of the electron

C) False. Does it move

D) True. Explain the oscillation and movement in the direction of the wave

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Tutorial Exercise An unstable atomic nucleus of mass 1.83 10-26 kg initially at rest disintegrates into three particles. One of
kogti [31]

Answer:

A) v3 = -[6.29 × 10^(6)]j^ - [7.06 × 10^(6)]i^

B) K_total = 373.08 × 10^(-15) J

Explanation:

We are given;

Mass of unstable atomic nucleus; M = 1.83 × 10^(-26) kg

Mass of first particle; m1 = 5.03 × 10^(-27) kg

Speed of first particle in y-direction; v1 = (6 × 10^(6) m/s) j^

Mass of second particle; m2 = 8.47 × 10^(-27) kg

Speed of second particle in x - direction; v2 = (4 × 10^(6) m/s) i^

Now, we don't have the mass of the third particle but since we are told the unstable atomic nucleus disintegrates into 3 particles, thus;

M = m1 + m2 + m3

1.83 × 10^(-26) = (5.03 × 10^(-27)) + (8.47 × 10^(-27)) + m3

m3 = (1.83 × 10^(-26)) - (13.5 × 10^(-27))

m3 = 4.8 × 10^(-27) kg

A) Applying law of conservation of momentum, we have;

MV = (m1 × v1) + (m2 × v2) + (m3 × v3)

Now, the unstable atomic nucleus was at rest before disintegration, thus V = 0 m/s.

Thus, we now have;

0 = (m1 × v1) + (m2 × v2) + (m3 × v3)

We want to find the velocity of the third particle v3. Let's make it the subject of the formula;

v3 = [(m1 × v1) + (m2 × v2)]/(-m3)

Plugging in the relevant values, we have;

v3 = [(5.03 × 10^(-27) × 6 × 10^(6))j^ + (8.47 × 10^(-27) × 4 × 10^(6))i^]/(-4.8 × 10^(-27))

v3 = [(30.18 × 10^(-21))j^ + (33.88 × 10^(-21))i^]/(-4.8 × 10^(-27))

v3 = -[6.29 × 10^(6)]j^ - [7.06 × 10^(6)]i^

B) Formula for kinetic energy is;

K = ½mv²

Now,total kinetic energy is;

K_total = K1 + K2 + K3

K1 = ½ × 5.03 × 10^(-27) × (6 × 10^(6))²

K1 = 90.54 × 10^(-15) J

K2 = ½ × 8.47 × 10^(-27) × (4 × 10^(6))²

K2 = 67.76 × 10^(-15)

To find K3, let's first find the magnitude of v3 because it's still in vector form.

Thus;

v3 = √[(-6.29 × 10^(6))² + (-7.06 × 10^(6))²]

v3 = 9.46 × 10^(6) m/s

K3 = ½ × 4.8 × 10^(-27) × (9.46 × 10^(6))²

K3 = 214.78 × 10^(-15) J

K_total = (90.54 × 10^(-15)) + (67.76 × 10^(-15)) + (214.78 × 10^(-15))

K_total = 373.08 × 10^(-15) J

7 0
3 years ago
True or False: A chemical reaction always happens when two substances are combined. (please help fast this is a test)
Makovka662 [10]

Answer:

no not always sometimes they react at all so false I hope I helped :)

6 0
3 years ago
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The acceleration of an object is constant when its velocity is :
emmasim [6.3K]

Answer:

B. changing by a constant amount each second

Explanation:

thats my answer

5 0
3 years ago
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A body accelerates uniformly from rest at 2m/s square. calculate it's velocity after traveling 9m.​
Talja [164]

Answer:

6m/s

Explanation:

Given parameters:

Initial velocity  = 0m/s

Acceleration  = 2m/s²

Distance  = 9m

Unknown:

Final velocity = ?

Solution:

To solve this problem, we use the expression below:

         v²  = u²  + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

        v²   = 0² + (2 x 2 x 9) = 36

        v  = 6m/s

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3 years ago
State the success of j j Thompson model theory​
vovikov84 [41]

Answer:

Thomson's atomic model was successful in explaining the overall neutrality of the atom. However, its propositions were not consistent with the results of later experiments. In 1906, J. J. Thomson was awarded the Nobel Prize in physics for his theories and experiments on electricity conduction by gases.

Summary. J.J. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. Thomson proposed the plum pudding model of the atom, which had negatively-charged electrons embedded within a positively-charged "soup."

4 0
3 years ago
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