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2 years ago

PLEASE HURRY THIS IS URGENT

Physics

1 answer:

Irina-Kira [14]2 years ago

7 0

3. Rubbing Sticks together to create a fire.

5. Gravity.

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when a hockey stick strike a hockey puck and sends it towards the goalie, (thermal, mechanical) energy is being transferred from

velikii [3]

Answer:

Yes... definitely true.. can you tell me what is the question..

Explanation:

Please mark me brainliest :D

And also.. I would appreciate it if you give me 5 stars and a thanks.. :D

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2 years ago

When describing electromagnetic radiation, there is a(n) _____________ relationship between wavelength and frequency and the gre

disa [49]

Its actually C. I did the question on USA test prep and it said the correct answer was C.

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3 years ago

Read 2 more answers

What are the coordinates of the point that is 1/5 of the way from A(-7,-4) to B(3, 6)?

Olegator [25]

Answer:

coordinate will be

r = (1.33,4.33)

Explanation:

As we know that if a point will divide two given coordinates in m : n ratio

then in that case the point is given as

$x = \frac{mx_1 + nx_2}{m+n}$

$y = \frac{my_1 + ny_2}{m+n}$

here we know that two points are

(-7, -4) and (3, 6)

and the ratio is given as 1 : 5

now from above formula we will have

$x = \frac{1(-7) + 5(3)}{1 + 5} = 1.33$

$y = \frac{1(-4) + 5(6)}{1 + 5} = 4.33$

so coordinate will be

$r = (1.33, 4.33)$

7 0

3 years ago

Identify and name the global wind belts. A. B. C. D. E. F. G.

Yuri [45]

Answer:

Explanation:

That is is the equator, prolly

6 0

2 years ago

Equations E = 1 2πε0 qd z3 and E = 1 2πε0 P z3 are approximations of the magnitude of the electric field of an electric dipole,

tamaranim1 [39]

Answer:

The ratio of $E_{app}$ and $E_{act}$ is 0.9754

Explanation:

Given that,

Distance z = 4.50 d

First equation is

$E_{act}=\dfrac{qd}{2\pi\epsilon_{0}\times z^3}$

$E_{act}=\dfrac{Pz}{2\pi\epsilon_{0}\times (z^2-\dfrac{d^2}{4})^2}$

Second equation is

$E_{app}=\dfrac{P}{2\pi\epsilon_{0}\times z^3}$

We need to calculate the ratio of $E_{act}$ and $E_{app}$

Using formula

$\dfrac{E_{app}}{E_{act}}=\dfrac{\dfrac{P}{2\pi\epsilon_{0}\times z^3}}{\dfrac{Pz}{2\pi\epsilon_{0}\times (z^2-\dfrac{d^2}{4})^2}}$

$\dfrac{E_{app}}{E_{act}}=\dfrac{(z^2-\dfrac{d^2}{4})^2}{z^3(z)}$

Put the value into the formula

$\dfrac{E_{app}}{E_{act}}=\dfrac{((4.50d)^2-\dfrac{d^2}{4})^2}{(4.50d)^3\times4.50d}$

$\dfrac{E_{app}}{E_{act}}=0.9754$

Hence, The ratio of $E_{app}$ and $E_{act}$ is 0.9754

8 0

2 years ago