Given that,
s = √(2t + 1)
Time, t = 4 s
Acceleration , a = ??
Since,
Acceleration = velocity / time
Velocity = distance/ time
Acceleration = distance/ time²
s/t² = √(2t+1)/t²
putting t = 4 sec, we have
a = √(2*4+1)/4²
a = √(5)/16
a= 0.139 ft/s²
Therefore, acceleration of the given particle will be 0.139 feet/ second².
Answer:
x positive and y negative I think
Explanation:
Answer:
23 m/s
Explanation:
First, find the time it takes for the car to fall 40 meters.
y = y₀ + v₀ t + ½ at²
0 = 40 + (0) t + ½ (-9.8) t²
0 = 40 − 4.9 t²
t = 2.89 s
Next, find the velocity needed to travel 65 meters in that time.
x = x₀ + v₀ t + ½ at²
65 = 0 + v₀ (2.89) + ½ (0) (2.89)²
v₀ = 22.75 m/s
Rounding to two significant figures, the car's initial speed was 23 m/s.
Answer:
(a) 31.44 m/s (b) 164.74 m/s²
Explanation:
Given that,
The diameter of a disk, d = 12 cm
Radius, r = 6 cm
Angular speed = 5.24 rad/s
(a) Linear speed,
(b) Centripetal acceleration,
I believe it is the 2nd one because the ground purifies it over a period of a little while.