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KIM [24]
3 years ago
10

A 3.06kg wood block is pressed against a vertical wood wall by a force applied at angle ϕ=32.6° to the horizontal. If the block

is initially at rest, and μs=0.313, what force would you need to apply to begin moving the box up the wall?
Physics
1 answer:
Annette [7]3 years ago
8 0

Let applied force against the wall is F

now the Normal force on the block is given by

F_n = F cos32.6

now friction force on the block will be given as

F_f = \mu * F_n

F_f = 0.313* (F cos32.6)

now net downwards force on the block will be

F_d= F_f + mg

F_d = 0.313*(Fcos32.6) + 3.06*9.8

F_d = 0.264F + 29.99

now this net downward force must be counterbalanced by upwards applied force

F_u = F_d

Fsin32.6 = 0.264F + 29.99

0.275*F = 29.99

F = 109.1 N

<em>so it required 109.1 N force to move it upwards</em>

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Scorpion4ik [409]

According to the following formula, the answer is 2,300 g or 2.3 kg:

Volume (m)/Mass (m) Equals Density (p) (V)

Here, the density is 1.15 g/mL, allowing the formula described above to result in a mass of 2.00 L:

p=m/V

1.15 g/mL is equal to x g/2.00 L or x g/2,000 mL.

2,000 mL of x g = 1.15 g of g/mL

2.3 kg or 2,300 g for x g.

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5 0
1 year ago
He does whatever a spider can. Spider-Man, who has a mass of 76 [kg], is clinging onto an inclined wall forming an inclination a
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Explanation:

Given

mass of man=76 kg

\theta =50^{\circ}

As man is standing over inclined building therefore

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Force perpendicular to inclined wall

F=mgcos\theta =76\times 9.8\times \sin 50

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4 0
3 years ago
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Answer:

(a) Most reactive {}       Metal B

{}                                    Metal D

{}                                    Metal A

Least reactive {}           Metal C

(b) (i) Bubbles should form very slowly

(ii) No reaction takes place

Explanation:

(a) The given metals arranged in their order of reactivity are;

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{}                               Metal D

{}                               Metal A

Least reactive {}      Metal C

The other of reactivity is based on the nature of their reactivity of the metals in air

(b) (i) Based on the reactivity of the metals in air, whereby metal A reacts very slowly and an oxide is formed, we have that, based on the reactivity of the metal A, when mixed with dilute hydrochloric acid, bubbles should form very slowly

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⚠️Pls help me this is due soon!⚠️
nika2105 [10]

professional is the answer

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6 0
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