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kirza4 [7]
3 years ago
7

Choose the aqueous solution that has the highest boiling point. These are all solutions of nonvolatile solutes and you should as

sume ideal van't Hoff factors where applicable. A. 0.100 m K2SO4 B. 0.100 m LiNO3 C. 0.200 m C3H8O3 D. 0.060 m Na3PO4 E. They all have the same boiling point.
Chemistry
1 answer:
UNO [17]3 years ago
3 0

Answer: 0.100 m K_2SO_4

Explanation:

Elevation in boiling point is given by:

\Delta T_b=i\times K_b\times m

\Delta T_b=T_b-T_b^0 = Elevation in boiling point

i= vant hoff factor

K_b = boiling point constant

m= molality

1. For 0.100 m K_2SO_{4}

K_2SO_4\rightarrow 2K^{+}+SO_4^{2-}  

, i= 3 as it is a electrolyte and dissociate to give 3 ions. and concentration of ions will be 3\times 0.100=0.300

2. For 0.100 m LiNO_3

LiNO_3\rightarrow Li^{+}+NO_3^{-}  

, i= 2 as it is a electrolyte and dissociate to give 2 ions, concentration of ions will be 2\times 0.100=0.200

3.  For 0.200 m C_2H_8O_3

, i= 1 as it is a non electrolyte and does not dissociate, concentration of ions will be 1\times 0.200=0.200

4. For 0.060 m Na_3PO_4

Na_3PO_4\rightarrow 3Na^{+}+PO_4^{3-}  

, i= 4 as it is a electrolyte and dissociate to give 4 ions. and concentration of ions will be 4\times 0.060=0.24m

Thus as concentration of solute is highest for K_2SO_4 , the elevation in boiling point is highest and thus has the highest boiling point.

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At what temperature scale Fahrenheit shows double than Kelvin scale​
sergij07 [2.7K]

Answer:

-12.3 degrees F.

Originally Answered: At what temperature does the Kelvin scale read double the Fahrenheit reading? -24.6 degrees C = -12.3 degrees F.

Explanation:

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3 years ago
Nhóm axit nào tác dụng với mg tạo ra h2o
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2 years ago
A group of students working in a chemistry lab are planning a procedure to
NARA [144]

use a strong base to neutralize, like NaOH, KOH, etc

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1 year ago
An experiment was conducted to determine the density of a rock sample. The table shows a partial record of the experiment.
mart [117]

Answer: the density of the rock

55.91g/ml

Explanation:

The density of the rock after it had being placed in the cylinder of water so the calculation should look like this:

Volume of water substract the mass of the rock:

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So the density of the rock is 55.91g/ml

5 0
2 years ago
Dry air (0% humidity) is approximately 78% N2, 21% O2, and 1% Ar by moles. Calculate the molar mass and density of dry air at 0
gtnhenbr [62]

Answer:

The molar mass of dry air = 28.94

Density = 1.29

Explanation:

Mm of N2= 28, Mm of O2= 32, Mm Ar= 39.9

78% of N2 by mole give = 0.78×28= 21.84

21% of O2 by mole give = 0.21× 32= 6.72

1% of At by mole give = 0.01× 39= 0.39

Hence overall molecular weight of air = 21.84+6.72+0.39= 28.94

Density = m/ v,

1- mole of air occupy 22.4dm^3 volume

Density= 28.94/22.4= 1.29

6 0
3 years ago
Read 2 more answers
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