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kirza4 [7]
2 years ago
7

Choose the aqueous solution that has the highest boiling point. These are all solutions of nonvolatile solutes and you should as

sume ideal van't Hoff factors where applicable. A. 0.100 m K2SO4 B. 0.100 m LiNO3 C. 0.200 m C3H8O3 D. 0.060 m Na3PO4 E. They all have the same boiling point.
Chemistry
1 answer:
UNO [17]2 years ago
3 0

Answer: 0.100 m K_2SO_4

Explanation:

Elevation in boiling point is given by:

\Delta T_b=i\times K_b\times m

\Delta T_b=T_b-T_b^0 = Elevation in boiling point

i= vant hoff factor

K_b = boiling point constant

m= molality

1. For 0.100 m K_2SO_{4}

K_2SO_4\rightarrow 2K^{+}+SO_4^{2-}  

, i= 3 as it is a electrolyte and dissociate to give 3 ions. and concentration of ions will be 3\times 0.100=0.300

2. For 0.100 m LiNO_3

LiNO_3\rightarrow Li^{+}+NO_3^{-}  

, i= 2 as it is a electrolyte and dissociate to give 2 ions, concentration of ions will be 2\times 0.100=0.200

3.  For 0.200 m C_2H_8O_3

, i= 1 as it is a non electrolyte and does not dissociate, concentration of ions will be 1\times 0.200=0.200

4. For 0.060 m Na_3PO_4

Na_3PO_4\rightarrow 3Na^{+}+PO_4^{3-}  

, i= 4 as it is a electrolyte and dissociate to give 4 ions. and concentration of ions will be 4\times 0.060=0.24m

Thus as concentration of solute is highest for K_2SO_4 , the elevation in boiling point is highest and thus has the highest boiling point.

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padilas [110]

Answer:

The new volume of the gas is 32L

Explanation:

P1 = 16atm

V1 = 4L

P2 = atm

V2 = ?

According to Boyle's law, the volume of a given mass of gas is inversely proportional to its volume provided the temperature remains constant.

P1 * V1 = P2 * V2

V2 = (P1 * V1) / P2

V2 = (16 * 4) / 2

V2 = 64 / 2

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The new volume of the gas is 32L

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3 years ago
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alina1380 [7]

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7 0
2 years ago
The radius of a vanadium atom is 130 pm. How many vanadium atoms would have to be laid side by side to span a distance of 1.30 m
monitta

Answer:

5 000 000 (5 million atoms)

Explanation:

Let us assume that a vanadium atom has a spherical shape.

diameter of a sphere = 2 x radius of the sphere

Thus,

Radius of a vanadium atom = 130 pm

                                              = 130 x 10^{-12} m

The diameter of a vanadium atom = 2 x radius

                                                         = 2 x 130 x 10^{-12}

                                               = 260 x 10^{-12} m

Given a distance of 1.30 mm = 1.30 x 10^{-3} m,

The number of vanadium atoms required to span the distance = \frac{1.3*10^{-3} }{260*10^{-12} }

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Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.

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3 years ago
What happens to the atomic radius of elements as you move from left to right across a period?​
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