1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bija089 [108]
2 years ago
7

This means that if there are 15.0 g of starting chemicals, also known as

Chemistry
1 answer:
Serggg [28]2 years ago
4 0

Answer:

Reactants

Explanation:

"Starting chemicals", the substances present before a reaction occurs, are called reactants.

The results of the reaction are called products, which you would also have 15.0g.

You might be interested in
What does the law of reflection state?
Anestetic [448]

Answer:

B is the correct answer

7 0
2 years ago
Read 2 more answers
If the reaction N2 (g) + 3 H2 (g) --> 2 NH3 (g) has the concentrations 1.1 M for nitrogen, 0.75 M for hydrogen and 0.25 M fo
Luba_88 [7]

<u>Answer:</u> The value of K_c is 0.136 and is reactant favored.

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For the chemical reaction between carbon monoxide and hydrogen follows the equation:

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

The expression for the K_{c} is given as:

K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}

We are given:

[NH_3]=0.25M

[H_2]=0.75M

[N_2]=1.1M

Putting values in above equation, we get:

K_c=\frac{(0.25)^2}{1.1\times (0.75)^3}

K_c=0.135

There are 3 conditions:

  • When K_{c}>1; the reaction is product favored.
  • When K_{c}; the reaction is reactant favored.
  • When K_{c}=1; the reaction is in equilibrium.

For the given reaction, the value of K_c is less than 1. Thus, the reaction is reactant favored.

Hence, the value of K_c is 0.136 and is reactant favored.

4 0
3 years ago
Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following:
Alja [10]

The electron-group arrangement of CO₃²⁻ is trigonal planar. The molecular shape is trigonal planar, and the ideal bond angle(s) is CO₃²⁻ is 120°

<h3>What is the molecular geometry of a compound?</h3>

The position of the compound's electrons and nuclei can be seen in the molecular geometry. It demonstrates how the form of the complex is created by the interaction of electrons and nuclei.

Here, according to the VSEPR  theory, the shape of the carbonate ion is trigonal planar. The carbon will be in the center.

Thus, the electron-group arrangement and the shape of the carbonate ion are trigonal planar. The bond angle will be 120°.

To learn more about molecular geometry, refer to the link:

brainly.com/question/16178099

#SPJ4

6 0
1 year ago
5250000 determine the number of significant figures
Shtirlitz [24]

Answer:

3 significant figures

7 0
2 years ago
Which is a compound that contains carbon?
Anastaziya [24]

carbon dioxide, that is what I found

7 0
2 years ago
Other questions:
  • Which equation represents a double replacement reaction
    7·2 answers
  • What inspired Mendeleev to create his organization for the elements
    11·1 answer
  • A scientist is tracking an object orbiting the sun that is found between mars and Jupiter. Which additional feature can be used
    10·1 answer
  • Antarctica, almost completely covered in ice, has an area
    11·1 answer
  • Given the equation I = Q/t, solve for t.
    9·1 answer
  • Hector claims that a single sodium ion and a single oxygen ion do not bond together to form a stable binary ionic compound. Is h
    12·2 answers
  • Which resulted from the study of chemistry?
    7·2 answers
  • A. Direction: Identify the word or phrase being described in the sentence. Write your
    9·1 answer
  • During summer water kept in an earthen pot become cool because of the phenomenon of​
    6·1 answer
  • Explain what "LEO the lion goes GER" means based upon what you have learned
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!