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aliya0001 [1]
3 years ago
5

Which statement must be mentioned in explaining why amphipathic molecules line up at a water surface?Which statement must be men

tioned in explaining why amphipathic molecules line up at a water surface?
A. Nonpolar groups repel water.
B. Nonpolar groups attract one another.
C. Polar groups attract one another.
D. Polar groups repel water.
E. All of the above.
Chemistry
2 answers:
Ray Of Light [21]3 years ago
3 0

Answer:

it would be c

Explanation:

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valentina_108 [34]3 years ago
3 0

Answer: Option (C) is the correct answer.

Explanation:

An amphipathic molecules is defined as the molecule that contains both polar and non-polar parts.

For example, phospholipids are amphipathic molecules as they contain non-polar fatty acids known as tails and polar phosphate known as heads.

In amphipathic molecules, the polar water molecules tend to pull towards each other. As a result, non-polar parts tend to move away into the air.

Therefore, we can conclude that amphipathic molecules line up at a water surface because polar groups attract one another.

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A compound that is composed of molybdenum (Mo) and oxygen (O) was produced in a lab by heating molybdenum over a Bunsen burner.
irakobra [83]
First, we determine the mass of each element from the data collected. We can get the mass of molybdenum Mo from the difference between the mass of crucible and molybdenum and the mass of crucible:
     Mass of molybdenum = 39.52 – 38.26 = 1.26 g Mo

We can calculate for the mass of molybdenum oxide from the difference between the mass of crucible and molybdenum oxide and the mass of crucible:
     Mass of molybdenum oxide = 39.84 – 38.26 = 1.58g 

We can now compute for the mass of oxygen O by subtracting the mass of molybdenum from the mass of molybdenum oxide:
     Mass of oxygen in molybdenum oxide = 1.58 – 1.26 = 0.32g O

To convert mass to moles, we use the molar mass of each element.
     1.26 g Mo * 1 mol Mo / 95.94 g Mo = 0.0131 mol Mo
     0.32 g O * 1 mol O / 15.999 g O = 0.0200 mol O

0.0131 mol is the smallest number of moles. We divide each mole value by this number:
     0.0131 mol Mo / 0.0131 = 1
     0.0200 mol O / 0.0131 = 1.53

Multiplying these results by 2 to get the lowest whole number ratio,
     0.0131 mol Mo / 0.0131 = 1 * 2 = 2
     0.0200 mol O / 0.0131 = 1.5 * 2 = 3
Thus, we can write the empirical formula as Mo2O3.
5 0
4 years ago
Read 2 more answers
A helium-filled weather balloon has a volume of 512 L at 18.9°C and 756 mmHg. It is released and rises to an altitude of 2.14 km
vazorg [7]

633.97 L

Explanation:

Well use the combined gas law;

P₁V₁T₁ = P₂V₂T₂

We need to change the temperatures into Kelvin;

18.9°C= 292.05 K

5.9°C = 279.05 K

756 * 512 * 292.05 = 639 * V₂ * 279.05

113,044,377.6 = 178,312.95 V₂

V₂ = 113,044,377.6 / 178,312.95

V₂ = 633.97 L

3 0
3 years ago
Read 2 more answers
Calculate the following quantity: molarity of a solution prepared by diluting 45.45 mL of 0.0404 M ammonium sulfate to 550.00 mL
dybincka [34]

Answer:

M_2=3.34x10^{-3}M

Explanation:

Hello!

In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:

M_1V_1=M_2V_2

Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:

M_2=\frac{M_2V_2}{V_1} =\frac{45.45mL*0.0404M}{550.00mL}\\\\M_2=3.34x10^{-3}M

Best regards!

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It well be 9025 because it will dissolve in 0.8 hcl soluiton

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Duncan knows that it takes 36400 cal of energy to heat a pint of water from room temperature to boiling. However, Duncan has pre
antiseptic1488 [7]
However, Duncan has prepared ramen noodles so many times he does not need to measure the water carefully. If he happens to heat 0.850 ...
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