Question 5

What would the volume of gas be at 150 c if it had a volume of 693 ml at 45 c

marissa [1.9K]

Answer:

$\boxed{\text{922 mL}}$

Explanation:

The pressure is constant, so we can use Charles' Law to calculate the volume.

$\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}$

Data:

V₁ = 693 mL; T₁ = 45 °C

V₂ = ?; T₂ = 150 °C

Calculations:

(a) Convert temperature to kelvins

T₁ = ( 45 + 273.15) = 318.15 K

T₂ = (150 + 273.15) = 423.15 K

(b) Calculate the volume

$\dfrac{ 693}{318.15} = \dfrac{ V_{2}}{423.15}\\\\2.178 = \dfrac{ V_{2}}{423.15}\\\\V_{2} = 2.178 \times 423.15 = \boxed{\textbf{922 mL}}$

5 0

3 years ago

A student is trying to develop a model of an instant heat pack. What is the essential characteristic of the chemical reaction th

Lana71 [14]

The standard enthalpy of reaction should be negative.

<h3>What is enthalpy?</h3>

A thermodynamic quantity equivalent to the total heat content of a system. It is equal to the internal energy of the system plus the product of pressure and volume.

Inside the heat pack are two chemicals that get mixed when you smush them together. As they mix, some weak bonds are broken, which takes a little bit of energy. But new, stronger bonds form which release energy. Releasing that energy causes the surroundings to heat up.

Hence, option B is correct.

Learn more about enthalpy here:

brainly.com/question/13775366

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3 0

2 years ago

A 0.15 m aqueous solution of a weak acid has a freezing point of -0.31 °C. What is the percent ionization of this weak acid at t

tensa zangetsu [6.8K]

Answer:

11%

Explanation:

1) Calculate van 't Hoff factor:

Δt = i Kf m

0.31 = i (1.86) (0.15)

i = 1.111

2) Calculate value for [H+]:

CCl3COOH ⇌ H+ + CCl3COO¯

total concentration of all ions in solution equals:

(1.11) (0.15) = 0.1665 m

This is a molality, but we will act as if it a molarity since we will assume the density of the solution is 1.00 g/cm3, which makes the molarity equal to the molality.

0.1665 = (0.15 − x) + x + x

x = 0.0165 M

3) Calculate the percent dissociation:

0.0165/ 0.15 = 11 %

4 0

3 years ago

For the reaction IO3–(aq) + 5 I–(aq) + 6 H+(aq) → 3 I2(aq) + 3 H2O(l) the rate of disappearance of I–(aq) at a particular time a

scoray [572]

Answer: The rate of appearance of $I_2(aq)$ is $1.44\times 10^{-3}mol/Ls$

Explanation:

Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction:

$IO_3^-(aq)+5I^-(aq)+6H^+(aq)\rightarrow 3I_2(aq)+3H_2O(l)$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

$Rate=-\frac{1d[I^-]}{5dt}=+\frac{d[I_2]}{3dt}$

Given: $-\frac{d[I^-]}{dt}]$ = $2.4\times 10^{-3}mol/Ls$

$+\frac{d[I_2]}{dt}=-\frac{3d[I^-]}{5dt}=-\frac{3}{5}\times 2.4\times 10^{-3}mol/Ls=1.44\times 10^{-3}mol/Ls$

The rate of appearance of $I_2(aq)$ is $1.44\times 10^{-3}mol/Ls$

6 0

3 years ago

Difference between rapid combustion and spontaneous combustion.

statuscvo [17]

Answer: The difference between rapid combustion and spontaneous combustion...

Explanation:

Rapid combustion is a form of combustion, otherwise known as a fire, in which large amounts of heat and light energy are released, which often results in a flame.Whereas spontaneous combustion is the ignition of organic matter (e.g. hay or coal) without apparent cause, typically through heat generated internally by rapid oxidation.

6 0

2 years ago