Answer:
0.07789 M is the sodium hydroxide concentration.
Explanation:
Mass of potassium hydrogen phthalate = 0.6986 g
Molar mass of potassium hydrogen phthalate = 204.22 g/mol
Moles of potassium hydrogen phthalate = 
According to reaction , 1 mole og KHp reactswith 1 mole of NaOH , then 0.003421 moles of KHp will react with :
Moles of NaOH = 0.003421 mole
Volume of NaOH solution = 43.92 ml = 0.04392 L ( 1 mL = 0.001L)
Concentration of NaOH :
0.07789 M is the sodium hydroxide concentration.
Answer:
Final volume = V₂ = 8.2L
Explanation:
Given data:
Initial volume = 12.3 L
Initial pressure = 40.0 mmHg
Final volume = ?
Final pressure = 60.0 mmHg
Solution:
The given problem will be solved through the Boyle's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
40.0 mmHg × 12.3 L = 60.0 mmHg × V₂
V₂ = 40.0 mmHg × 12.3 L / 60.0 mmHg
V₂ = 492 mmHg. L / 60.0 mmHg
V₂ = 8.2L
BF3 acts as a Lewis acid when it accepts the lone pair of electrons that NH3 donates.
Answer:
99.3%
Explanation:
The percent by mass of the solute can be expressed as:
- % mass =
* 100%
And for this problem:
- Mass of Solute = Mass of sodium lithium chloride = 29 g
- Mass of Solvent = Mass of Water
So to calculate the percent by mass first we need to <u>calculate the mass of water</u>, to do so we use its<em> density</em> (1 g/L):
- 202 mL is equal to (202/1000) 0.202 L.
Density water = mass water / volume
- 1 g/L = mass water / 0.202 L
Now we have all the data required to <u>calculate the % mass:</u>
- % mass =
* 100 % = 99.3%
