<span><span>Atomic number36,</span><span>Atomic mass<span>83.80 g.mol -1,</span></span><span>Density<span>3.73 10-3 g.cm-3 at 20°C,</span></span><span>Melting point- 157 °C,</span><span>Boiling point<span>- 153° C</span></span></span>
Answer:
fe3o4+4h2 - 3fe + 4h2o
therefore coefficient is 4
Answer:
Their melting and boiling points of alkanes are relatively low. The higher the molecular weight (the greater the number of carbons), the higher the boiling point.
Answer:
The mass percent refers to the mass of an element in a compound. It is one of the ways of expressing concentration. The mass percent of the solution provides the percentage of the amount of solute present in grams of solution.
The mass percentage of S=40.06 % and the molar mass of S= 32. By applying the formula of mass percent,we can calculate the molar mass of M.
The molar mass of M=159.76-64=95.76
We know that the element of molybdenum has molar mass of 96. Therefore, the element M is <u>Molybdenum.</u>
The boiling point depends on the strength of the intermolecular forces holding the molecules together. Greater the force, higher is the boiling point.
The intermolecular force increases in the order shown below:
ion-ion > H-bonding > dipole-dipole > London dispersion
CH3CN is a polar molecule with strong dipole-dipole forces
CH3CH2CH3 is non-polar held by london dispersion
Ar exist as a gas. It will have a lowest boiling point
Thus the order of decreasing b.pt is:
CH3CN > CH3CH2CH3 > Ar
* 100%
* 100 % = 99.3%