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belka [17]
3 years ago
8

A remote-controlled boat traveled 18 feet heading west and 24 feet heading south, totaling 42 feet over the course of 10 seconds

. Heading west, the boat traveled at an average speed of 3 feet per seconds less than its speed heading south. What was the average speed of the boat heading west? (Do not include the units in your response.)
Physics
1 answer:
Dominik [7]3 years ago
3 0

Answer:

3 ft/s

Explanation:

given,

distance in west, d₁ = 18 ft

distance in south, d₂ = 24 ft

time taken to travel 42 ft = 10 s

speed of boat in north = x ft/s

Speed of the boat when heading west = (x - 3) ft/s

Average\ speed = \dfrac{total\ distance}{total\ time}

v_{avg}= \dfrac{42}{10}

v_{avg}= 4.2\ ft/s

again using the above formula

now, total time

t = t₁ + t₂

10 = \dfrac{18}{x-3} + \dfrac{24}{x}

on simplifying

10 x² -72 x + 72 = 0

On solving the above equation we get

x = 6 ft/s

Hence, speed of boat in west direction, 6 -3 = 3 ft/s

           speed of boat in south direction = 6 ft/s

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2 years ago
The latent heat of fusion of water at 0 °C is 6.025 kJ mol'' and the molar heat
Scilla [17]

Answer:

\Delta H_{tot} = 2258.025\,kJ

Explanation:

The amount of heat released from water is equal to the sum of latent and sensible heats. Let suppose that water is initially at a temperature of 25^{\circ}C. Then:

\Delta H_{tot} = \Delta H_{s, w} + \Delta H_{f,w} + \Delta H_{s,i}

\Delta H_{tot} = n\cdot (c_{w}\cdot \Delta T_{w} + L_{f} + c_{i}\cdot \Delta T_{i})

Finally, the amount of heat released from water is now computed by replacing variables:

\Delta H_{tot} = (1\,mol)\cdot \left[\left(75.3\,\frac{kJ}{mol\cdot K} \right)\cdot (25^{\circ}C-0^{\circ}C)+ 6.025\,\frac{kJ}{mol} + \left(37.7\,\frac{kJ}{mol\cdot K} \right)\cdot (0 + 10^{\circ}C)\right]\Delta H_{tot} = 2258.025\,kJ

4 0
3 years ago
Write four (4) strategies on how can we manage land use around South Florida. For each strategy, explain it's benefits to the en
a_sh-v [17]

Answer:

What are some ways we can improve on our land use?

- Avoid deforestation and close the forest frontier.

The first-order priority is to end deforestation by closing the "forest frontier" or intact forests, to development.

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3 0
3 years ago
Find the magnitude of u × v and the unit vector parrallel to u × v in the direction of u × v. u = 2i + 2j - k, v = -i + k
IrinaVladis [17]

Answer:

magnitude = 3

unit vector = \frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}

Explanation:

Given vectors:

u = 2i + 2j - k

v = -i + k = -i + 0j + k

(a) u x v is the cross product of u and v, and is given by;

u X v = \left[\begin{array}{ccc}i&j&k\\2&2&-1\\-1&0&1\end{array}\right]

u x v = i(2+0) - j(2 - 1) + k(0 - 2)

u x v = 2i - j - 2k

Now the magnitude of u x v is calculated as follows:

| u x v | = \sqrt{2^2 + (-1)^2 + (-2)^2}

| u x v | = \sqrt{4 + 1 + 4}

| u x v | = \sqrt{9}

| u x v | = 3

Therefore, the magnitude of u x v is 3

(b) The unit vector û parallel to u x v in the direction of u x v is given by the ratio of u x v and the magnitude of u x v. i.e

û = \frac{u X v}{|u X v|}        

u x v = 2i - j - 2k        [<em>calculated in (a) above</em>]

|u x v| = 3                   [<em>calculated in (a) above</em>]

∴ û = \frac{2i - j - 2k}{3}

∴ û = \frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}

4 0
3 years ago
A 125 W motor accelerates a block along a level, frictionless surface at an average speed of 5.0
Lelu [443]

Answer:

25N

Explanation:

Given parameters:

Power of the motor = 125W

Average speed  = 5m/s

Unknown:

Force supplied to the motor = ?

Solution:

 Work done is the force applied to move a body through a particular distance;

         Work done  = Force x distance

Also,

        Work done  = Power x time

 

So;

             Force x distance = Power  x time

  since force is the unknown;

            Force  = \frac{Power x time}{distance}

         Speed  = \frac{distance }{time}

             Force  = \frac{Power}{speed}

Now solve;

                Force  = \frac{125}{5}    = 25N

3 0
3 years ago
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