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Wittaler [7]
2 years ago
8

I need help with these question ASAP .. I have to get them done tonight because it is due tomorrow

Physics
1 answer:
Yuki888 [10]2 years ago
8 0

Answer:

It's letter B that's all I know

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Which scenario did not include a chemical change?
Jobisdone [24]

Answer:

what scenario i dont understand

Explanation:

step by step explenation

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3 years ago
1. What is the efficiency of a heat engine that does 1250 J of work and gives off 5250 J of heat to
vladimir2022 [97]

answer: in pic

explanation: found it here http://gaaq.weebly.com/uploads/7/8/8/4/78844490/chapter_11_q_as.pdf

7 0
3 years ago
Read 2 more answers
Use the passage to answer the question.
Studentka2010 [4]

This is not something that waves do because they need a medium to travel through, while particles do not.

<h3>How light travels in space?</h3>

A light travels without any medium while on the other hand, a medium is required for sound waves to move from oe place to another. Sound is a mechanical wave that cannot travel through a vacuum.

So we can conclude that electromagnetic waves like light do not require medium for its propagation.

Learn more about light here: brainly.com/question/19697218

3 0
2 years ago
Please help me with the question below
vampirchik [111]

Answer:

a cold air mass and a warm air mass merge together

6 0
3 years ago
How many photons will be required to raise the temperature of 1.8 g of water by 2.5 k ?'?
tatyana61 [14]
Missing part in the text of the problem: 
"<span>Water is exposed to infrared radiation of wavelength 3.0×10^−6 m"</span>

First we can calculate the amount of energy needed to raise the temperature of the water, which is given by
Q=m C_s \Delta T
where
m=1.8 g is the mass of the water
C_s = 4.18 J/(g K) is the specific heat capacity of the water
\Delta T=2.5 K is the increase in temperature.

Substituting the data, we find
Q=(1.8 g)(4.18 J/(gK))(2.5 K)=18.8 J=E

We know that each photon carries an energy of
E_1 = hf
where h is the Planck constant and f the frequency of the photon. Using the wavelength, we can find the photon frequency:
\lambda =  \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{3 \cdot 10^{-6} m}=1 \cdot 10^{14}Hz

So, the energy of a single photon of this frequency is
E_1 = hf =(6.6 \cdot 10^{-34} J)(1 \cdot 10^{14} Hz)=6.6 \cdot 10^{-20} J

and the number of photons needed is the total energy needed divided by the energy of a single photon:
N= \frac{E}{E_1}= \frac{18.8 J}{6.6 \cdot 10^{-20} J} =2.84 \cdot 10^{20} photons
4 0
3 years ago
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