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Leni [432]
3 years ago
7

13. For an object to appear transparent, what interaction must occur between light waves and the object they hit?

Physics
2 answers:
Svetlanka [38]3 years ago
6 0

Answer:

The answer is B

Explanation:

The absorption happens when photons from light hit atoms and molecules, and they vibrate because of that specific interaction. Then the heat ejects from the object in the format of thermal energy.

Arisa [49]3 years ago
3 0
They are absorbed answer is B
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What is meant by components of a vector?
topjm [15]

Answer:

Each part of a two-dimensional vector is known as a component. The components of a vector depict the influence of that vector in a given direction. The components of a vector depict the influence of that vector in a given direction.

Explanation:

hope this helps

3 0
4 years ago
Three 10-cm-long rods form an equilateral triangle. Two of the rods are charged to + 19 nC, the third to - 19 nC.What is the ele
Sveta_85 [38]
<span>We calculate the electric field as follows:
r = </span>√<span>(3)/6 x 19 cm = .05484 m 
The angle for the triangle would be 30 on each side.
tan(30) = r/(L/2) 

E' = kQ/{r*sqrt[(L/2)^2 + r^2]} = (8.99e9 x 15e-9) / {.05484 * sqrt[(.19/2)^2 + .003]}
</span>E' <span>= 22413 N/C
The value above is the electric field strength for a single rod at the center. 

|E'| = 22413 N/C 
E = 2|E'|sin(30) + |E'| = 49000 N/C</span>
5 0
3 years ago
Does high pressure rise and low pressure sink
sergeinik [125]
High pressure<span> is associated with sinking air, and </span>low pressure<span> is associated with </span>rising air t<span>he opposite occurs with </span>high pressure<span>. Air is moving away from the </span>high pressure<span> center at the surface so as a result, air from above must </span>sink <span>to take its place.</span>
6 0
3 years ago
Read 2 more answers
A closed curve encircles several conductors. The line integral around this curve is (image attached below)
Masteriza [31]

The net current in the conductors and the value of the line integral

  • I=\frac{3.2\cdot 10^{-4}}{4\pi \cdot 10^{-7}}=254.77\, A
  • The resultant remains same 3.2 *10^4 Tm

This is further explained below.

<h3>What is the net current in the conductors?</h3>

Generally,

To put it another way, the total current In flowing across a surface S (contained by C) is proportional to the line integral of the magnetic B-field (in tesla, T).

\oint_C \mathbf{B} \cdot \mathrm{d}\boldsymbol{\ell} = \mu_0 \iint_S \mathbf{J} \cdot \mathrm{d}\mathbf{S} = \mu_0I_\mathrm{enc}

I=\frac{3.2\cdot 10^{-4}}{4\pi \cdot 10^{-7}}=254.77\, A

B)

In conclusion, It is possible for the line integral to go around the loop in either direction (clockwise or counterclockwise), the vector area dS to point in either of the two normal directions and Ienc, which is the net current passing through the surface S, to be positive in either direction—but both directions can be chosen as positive in this example. The right-hand rule solves these ambiguities.

The resultant remains the same at 3.2 *10^4 Tm

Read more about conductors

brainly.com/question/8426444

#SPJ1

5 0
2 years ago
An insulated Thermos contains 140 cm3 of hot coffee at 85.0°C. You put in a 15.0 g ice cube at its melting point to cool the cof
Pavel [41]

Answer:

T = 69^o C

Explanation:

Here at thermal equilibrium we can say that thermal energy given by Hot coffee is equal to the thermal energy absorbed by ice cubes

So here we have

Q_{ice} = Q_{coffee}

now since ice cubes are added into coffee when it is at melting temperature

So here we can say that final temperature of coffee is T degree C

Now we have

m_1L + m_1c_1\Delta T_1 = m_2c_2\Delta T_2

here we have

m_1 = 15 gram

L = 333 kJ/kg = 333 J/g[/tex]

c_1 = c_2 = 4186 J/kg C = 4.186 J/g C

\Delta T_1 = T - 0

\Delta T_2 = 85 - T

now we have

15(333) + 15(4.186)(T - 0) = 140(4.186)(85 - T)

4995 + 62.79T = 49813.4 - 586.04T

648.83 T = 44818.4

T = 69^o C

6 0
3 years ago
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