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2 years ago

13. For an object to appear transparent, what interaction must occur between light waves and the object they hit?

Physics

2 answers:

Svetlanka [38]2 years ago

6 0

Answer:

The answer is B

Explanation:

The absorption happens when photons from light hit atoms and molecules, and they vibrate because of that specific interaction. Then the heat ejects from the object in the format of thermal energy.

Arisa [49]2 years ago

3 0

They are absorbed answer is B

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Which is an example of chemical energy from batteries to electromagnetic ( light ) energy?

TiliK225 [7]

Answer:

Explanation:

The batteries make it so the chemical energy is being passed into the flashlight allowing it to work as designed forming light.

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3 years ago

One mole of a substance contains 6.02 × 1023 protons and an equal number of electrons. If the protons could somehow be separated

Aleksandr [31]

Explanation:

it is almost zero .this is because the distance and the electrostatic force are inversely proportional

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1 year ago

A distorted 1kHz sine wave is represented by the equation: LaTeX: v(t) = 5sin(2 \pi 1000t) + 0.05sin(2 \pi 3000t)v ( t ) = 5 s i

vovikov84 [41]

Answer:

As given in the problem statement

frequency=1 KHz=1*10^3 Hz

V(t) is represented as

v(t) = 5sin(2 \pi 1000t) + 0.05sin(2 \pi 3000t)

v ( t ) = 5 s i n ( 2 π 1000 t ) + 0.05 s i n ( 2 π 3000 t )

Total harmonic distortion will be 234 Pi

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2 years ago

If you quadruple the temperature of a black body, by what factor will the total energy radiated per second per square meter incr

arlik [135]

In modern physics, as it was called "Stefan-Boltzmann law", the total energy radiated per unit surface area of a black body is directly proportional to the fourth power of the black body's temperature T

as:

$P\alpha T^4$

where: P is the power (total energy radiated per second per square meter) and T is the temperature of a black body.

then we can make a ratio between the state of before quadruple (with subscript 1) and after (with subscript 2) as:

$\frac{P_{1} }{P_{2} } =\frac{T_{1}^4 }{T_{2}^4}$

$T_{2}=4T_{1}$

Then

$\frac{P_{1} }{P_{2} } =\frac{T_{1}^4 }{(4T_{1})^4}$

then

$P_{2}=256*P_{1}$

The factor will the total energy radiated per second per square meter increase = 256

5 0

2 years ago

Solution A has a speciﬁc heat of 2.0 J/g◦C. Solution B has a speciﬁc heat of 3.8 J/g◦C. If equal masses of both solutions start

fgiga [73]

Answer: 2. Solution A attains a higher temperature.

Explanation: Specific heat simply means, that amount of heat which is when supplied to a unit mass of a substance will raise its temperature by 1°C.

In the given situation we have equal masses of two solutions A & B, out of which A has lower specific heat which means that a unit mass of solution A requires lesser energy to raise its temperature by 1°C than the solution B.

Since, the masses of both the solutions are same and equal heat is supplied to both, the proportional condition will follow.

We have a formula for such condition,

$Q=m.c.\Delta T$ .....................................(1)

where:

$\Delta T$ = temperature difference

Q= heat energy

m= mass of the body

c= specific heat of the body

Proving mathematically:

According to the given conditions

we have equal masses of two solutions A & B, i.e. $m_A=m_B$

equal heat is supplied to both the solutions, i.e. $Q_A=Q_B$

specific heat of solution A, $c_{A}=2.0 J.g^{-1} .\degree C^{-1}$

specific heat of solution B, $c_{B}=3.8 J.g^{-1} .\degree C^{-1}$

$\Delta T_A$ & $\Delta T_B$ are the change in temperatures of the respective solutions.

Now, putting the above values

$Q_A=Q_B$

$m_A.c_A. \Delta T_A=m_B.c_B . \Delta T_B\\\\2.0\times \Delta T_A=3.8 \times \Delta T_B\\\\ \Delta T_A=\frac{3.8}{2.0}\times \Delta T_B\\\\\\\frac{\Delta T_{A}}{\Delta T_{B}} = \frac{3.8}{2.0}>1$

Which proves that solution A attains a higher temperature than solution B.

7 0

2 years ago