Answer:
I = 27.65A < 40.59°
PowerFactor = 0.76
Explanation:
Current on the heating load is:
I1 = 30KW / 4KV = 7.5A < 0°
Current on the inductive load:
I2 = (150KVA*0.6) /4KV = 22.5A with an angle of acos(0.6)=53.1°
The sum of both currents is:
It = I1 + I2 = 7.5<0° + 22.5<53.1° = 27.65<40.59°
Now, the power factor will be:
pf = cos (40.59°) = 0.76
Answer:
i can't sorry
Explanation:
I didn't really pay attention in that class
Convert the given in SI units.
(44 ft/sec)(1 m/ 3.28 ft) = 13.41 m/sec
The distance traveled and the initial velocity can be related through the equation,
d = (Vf)² - (Vi)²/ 2a
where d is the distance, Vf is the final velocity, Vi is the initial velocity, a is the acceleration due to gravity. Substituting the known values from the given above,
d = ((0 m/s)² - (13.41 m/s)²)/ 2(-9.8 m/s²)
The value of d from the equation,
d = 9.17 meters
Convert this to feet,
d = (9.17 m)(3.28 ft / 1 m) = 30 ft
Answer: 30 ft
Answer:
D
Explanation:
Because I just had that answer
