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Kisachek [45]
2 years ago
11

1. How does the % error compare to the coded tolerance for your resistors​

Physics
1 answer:
Darya [45]2 years ago
6 0

Answer:

error ordied complete one orbit between maths

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A 2.0 kg wood block is launched up a wooden ramp that is inclined at a 30˚ angle. The block’s initial speed is 10 m/s. What vert
WARRIOR [948]

Answer:

The wood block reaches a height of 4.249 meters above its starting point.

Explanation:

The block represents a non-conservative system, since friction between wood block and the ramp is dissipating energy. The final height that block can reach is determined by Principle of Energy Conservation and Work-Energy Theorem. Let suppose that initial height has a value of zero and please notice that maximum height reached by the block is when its speed is zero.

\frac{1}{2}\cdot m \cdot v^{2} = m \cdot g\cdot h + \mu_{k}\cdot m\cdot g\cdot s \cdot \sin \theta

\frac{1}{2}\cdot v^{2} = g\cdot h + \mu_{k}\cdot g\cdot \left(\frac{h}{\sin \theta} \right)\cdot \sin \theta

\frac{1}{2}\cdot v^{2} = g\cdot h +\mu_{k}\cdot g\cdot h

\frac{1}{2}\cdot v^{2} = (1 +\mu_{k})\cdot g\cdot h

h = \frac{v^{2}}{2\cdot (1 + \mu_{k})\cdot g} (1)

Where:

h - Maximum height of the wood block, in meters.

v - Initial speed of the block, in meters per second.

\mu_{k} - Kinetic coefficient of friction, no unit.

g - Gravitational acceleration, in meters per square second.

m - Mass, in kilograms.

s - Distance travelled by the wood block along the wooden ramp, in meters.

\theta - Inclination of the wooden ramp, in sexagesimal degrees.

If we know that v = 10\,\frac{m}{s}, \mu_{k} = 0.20 and g = 9.807\,\frac{m}{s^{2}}, then the height reached by the block above its starting point is:

h = \frac{\left(10\,\frac{m}{s} \right)^{2}}{2\cdot (1+0.20)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

h = 4.249\,m

The wood block reaches a height of 4.249 meters above its starting point.

5 0
3 years ago
550 g of water at 105°C is poured into an 855 g aluminum container with an initial temperature of 11°C. The specific heat of alu
nexus9112 [7]

Answer:

54.22 kJ

Explanation:

In this case, we need to calculate the heat. The expression to use is:

Q = m * C * ΔT

Now, with the specific heat of water (4186 J/ kg K), we can calculate the temperature in which this occurs.

So:

Q = 0.550 * 4186 * (105 - T)

Q = 2302.3 (105 - T)

Q = 241,741.5 - 2302.3T

Now with the Aluminium:

Q = 0.855 * 900 * (T - 11)

Q = 769.5T - 8464.5

Now, with both equations, we solve for the final temperature:

769.5T - 8464.5 = 241,741.5 - 2302.3T

(2302.3 + 769.5)T = 241,741.5 + 8464.5

3071.8T = 250,206

T = 81.45 K

This is the temperature which the change occurs. Now, let's determine the amount of heat from water to Al:

Q = 241,741.5 - 2302.3(81.45)

Q = 54,219.17 J or simply 54.22 kJ.

5 0
3 years ago
Rock can be weathered and eroded in the rock cycle. What might happen with the resulting rock particles? A. New rock is formed f
Nostrana [21]
Answer: A
After rocks are eroded the particles turn into a sedimentary rock.
4 0
4 years ago
Read 2 more answers
All the bats living in a cave form a _______ of bats in the cave ecosystem.
kramer
I am sorry I cant find the answer. I was hoping to find the answer
8 0
4 years ago
An object of mass m is moving down an inclined plane that makes an angle they a with the horizontal and has height h. Which of t
Lera25 [3.4K]
The answer should be B. According to the conservation of energy, the energy cannot be created nor destroyed, but it can be transformed. Since the object is moving down, that means its height is decreasing, causing the potential energy decreasing and the kinetic energy  increasing to fulfill the conservation law. 
4 0
3 years ago
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