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Kisachek [45]
2 years ago
11

1. How does the % error compare to the coded tolerance for your resistors​

Physics
1 answer:
Darya [45]2 years ago
6 0

Answer:

error ordied complete one orbit between maths

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if a bullet of unknown mass is fired from a gun with 50m/s. such that the recoil of the gun is -0.3m/s if the mass of gun is 8 k
Mademuasel [1]

Answer:

1333.34 kg

Explanation:

Given that,

The mass of the gun, m = 8 kg

Speed of the bullet, V = 50 m/s

The recoil speed of the gun, v = -0.3 m/s

We need to find the mass of the bullet. Using the conservation of momentum to find it. Let M is the mass of the bullet.

mv=MV\\\\M=\dfrac{mv}{V}\\\\=\dfrac{50\times 8}{0.3}\\\\=1333.34\ kg

So, the mass of the bullet is 1333.34 kg.

4 0
3 years ago
The presence of dwarf galaxies around the Milky Way supports what picture of our galaxy’s formation?
elena-14-01-66 [18.8K]

Answer:

The presence of dwarf galaxies around the Milky Way supports what picture that our galaxy was formed by a coming together or combination of smaller systems

4 0
4 years ago
15.0 kg mass is displaced 3.00 m south and then 4.00 m west by a 10.0 N force. What is the total work done on the object?
masha68 [24]
<h2>Answer: D. 70.0 J</h2>

Explanation:

3.00 m + 4.00 m = 7.00 m x 10.0 N = 70.0 J

5 0
3 years ago
Some pipe organs create sounds lower than humans can hear. This ""infrasound"" can still create physical sensations. What is the
Dominik [7]

Answer: 17.59 Hz and 4.87 m

Explanation:

The fundamental frequency of the sound from an open-open pipe is given as

f= \frac{v}{2L}

where v= 343 m/s

L= 32 feet= \frac{32}{3.281} = 9.75 m

So,

f= \frac{343}{2*9.75} = 17.59 Hz

The length of open-closed tube is related to frequency by formula

f= \frac{v}{4L}

or L=\frac{v}{4f}

L= \frac{343}{4*17.59}

L= 4.87 m

8 0
4 years ago
You push a piano 5 meters across the floor with a force of 400 n. how much work have you done?
kobusy [5.1K]
2,000 j(apex)

i hope this was right
3 0
4 years ago
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